How much work does the electric field do in moving a proton from a point with a potential of +175 v to a point where it is -55 v
1 answer:
as per the question the proton is taken from the point of 175 volt to the point of -55 volt.
the work done in case of electric filed is given as
where Vab is the potential difference between two points.
Vab =Va-Vb
=175-[-55]volt
= 230 volt
the charge of proton is
hence the work done will be-
W=230 volt ×
=368.46 joule [ans]
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