All categories

3 years ago

Why do you think the temperature does not change much during a phase change?

Physics

2 answers:

Zielflug [23.3K]3 years ago

8 0

Answer:

By the there is no change in the temperature until the phase change is complete. It is that during the phase change the energy supplied is used only to seperate the molecules no part of it is used to increase the relating to a result from the motion energy of the molecules so it's temperature will not rise since the relating to a result from the motion energy of molecules remains the same .

I hope this might help u 

11111nata11111 [884]3 years ago

3 0

Answer:

It depends on where the temperature is dropping, in which body so to speak. Generally, the temperature adapts to the two bodies, for example if a hot piece of metal meets a cold one, the two will continue until they are at an equal temperature, an intermediate temperature.

You might be interested in

When an electron moves 2.5 m in the direction of an electric field, the change in electrical potential energy of the electron is

anygoal [31]

In the field of electromagnetism, when two charged plates that are situated opposite to each other by a certain distance, it forms an energy called the electric field. This energy is due to the difference in potential energy with respect to distance. Thus,

E = V/d

However, the voltage in volts is energy per coulomb. Thus,
V = (8x10-17 J/electron)*(1electron/1.60218x10^-19 C)
V = 499.32 volts

Therefore,

E = 499.32 volts /2.5 m
E = 199.73 N/C

The electric field that caused the change in potential energy is equal to 199.73 Newtons per Coulomb.

7 0

3 years ago

There are stars located in the center bulge of the Milky Way and the spiral arms of the Milky Way. What is the difference betwee

nadya68 [22]

Answer:

The stars at the center bulge are bigger and brighter than the stars in the arms.

Explanation:

5 0

3 years ago

Driving along a boring stretch of interstate in Illinois, you start experimenting using the average speed equation you learned i

astra-53 [7]

The average speed would be 33.29m/s.
The average speed equation is:

$Average speed = \frac{total distance}{total time}$

First you will need to solve for the distance you traveled in each scenario. So we can solve this by getting the product of speed and the time traveled.

Scenario 1:
Speed = 29m/s
Time = 120s
Distance = ?

Distance = (29m/s)(120s)
= 3,480m

Scenario 2
Speed = 35m/s
Time = 300s
Distance = ?

Distance = (35m/s)(300s)
= 10,500m

Now that you have the distance of both, you can solve for your average speed.

$Average speed = \frac{total distance}{total time}$
$= \frac{3,480m+10,500m}{120s+300s}$
$= \frac{13,980m}{420s}$
$= 33.29m/s$

5 0

3 years ago

Gravity can be described as..?

Tju [1.3M]

Answer:

Explanation:

Gravity is the force of attraction between two objects.

Each object creates a gravitational field in wich every other object is affected by it.

6 0

3 years ago

What is the gauge pressure of the water right at the point p, where the needle meets the wider chamber of the syringe? neglect t

Helen [10]

Missing details: figure of the problem is attached.

We can solve the exercise by using Poiseuille's law. It says that, for a fluid in laminar flow inside a closed pipe,

$\Delta P = \frac{8 \mu L Q}{\pi r^4}$

where:

$\Delta P$ is the pressure difference between the two ends

$\mu$ is viscosity of the fluid

L is the length of the pipe

$Q=Av$ is the volumetric flow rate, with $A=\pi r^2$ being the section of the tube and $v$ the velocity of the fluid

r is the radius of the pipe.

We can apply this law to the needle, and then calculating the pressure difference between point P and the end of the needle. For our problem, we have:

$\mu=0.001 Pa/s$ is the dynamic water viscosity at $20^{\circ}$

L=4.0 cm=0.04 m

$Q=Av=\pi r^2 v= \pi (1 \cdot 10^{-3}m)^2 \cdot 10 m/s =3.14 \cdot 10^{-5} m^3/s$

and r=1 mm=0.001 m

Using these data in the formula, we get:

$\Delta P = 3200 Pa$

However, this is the pressure difference between point P and the end of the needle. But the end of the needle is at atmosphere pressure, and therefore the gauge pressure (which has zero-reference against atmosphere pressure) at point P is exactly 3200 Pa.

8 0

3 years ago