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Evgesh-ka [11]
2 years ago
6

Why do you think the temperature does not change much during a phase change?

Physics
2 answers:
Zielflug [23.3K]2 years ago
8 0

Answer:

<em>By </em><em>the </em><em>there </em><em>is </em><em>no </em><em>change</em><em> </em><em>in </em><em>the </em><em>temperature</em><em> </em><em>until </em><em>the </em><em>phase </em><em>change </em><em>is </em><em>complete.</em><em> </em><em>It </em><em>is </em><em>tha</em><em>t</em><em> </em><em>during</em><em> </em><em>the </em><em>phase </em><em>change </em><em>the </em><em>energy </em><em>supplied </em><em>is </em><em>used </em><em>only </em><em>to </em><em>seperate </em><em>the </em><em>molecules </em><em>no </em><em>part </em><em>of </em><em>it </em><em>is </em><em>used </em><em>to </em><em>increase </em><em>the </em><em>relating </em><em>to </em><em>a </em><em>result </em><em>from </em><em>the </em><em>motion </em><em>energy</em><em> </em><em>of </em><em>the </em><em>molecules </em><em>so </em><em>it's </em><em>temperature</em><em> </em><em>will </em><em>not </em><em>rise </em><em>since </em><em>the </em><em>relating</em><em> to</em><em> a</em><em> </em><em>result</em><em> </em><em>from</em><em> the</em><em> </em><em>motion </em><em>energy </em><em>of </em><em>molecules </em><em>remains </em><em>the </em><em>same </em><em>.</em>

<em><u>I </u></em><em><u>hope </u></em><em><u>this </u></em><em><u>might </u></em><em><u>help </u></em><em><u>u</u></em><em> </em>

11111nata11111 [884]2 years ago
3 0

Answer:

It depends on where the temperature is dropping, in which body so to speak. Generally, the temperature adapts to the two bodies, for example if a hot piece of metal meets a cold one, the two will continue until they are at an equal temperature, an intermediate temperature.

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A length of wire is cut into five equal pieces. if each piece has a resistance of 0.45 ω, what was the resistance of the origina
azamat
Calculation, add them. 0.85 x 5 = 4.25 Ω
5 0
3 years ago
A hot-air balloon has a volume of 440 × 10^3 ^3. Calculate the buoyant force that the surrounding cold air exerts on the balloon
siniylev [52]

Answer:

Explanation:

Given that,

The volume of the balloon is

V = 440 × 10³ m³

Buoyant force F?

Given the density of the surrounding to be 2.58 kg/m³

ρ = 2.58 kg/m³

The buoyant force is the weight of water displaced and it is calculated using

F_b = ρVg

Where

F_b is buoyant force

ρ is density

V is the volume of the liquid displace.

g is the acceleration due to gravity

Then,

F_b = ρVg

F_b = 2.58 × 440 × 10³ × 9.81

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3 0
3 years ago
Help meh in this question plzzz <br>​
iragen [17]

The Moment of Inertia of the Disc is represented by I = \frac{15}{32}\cdot M\cdot R^{2}. (Correct answer: A)

Let suppose that the Disk is a Rigid Body whose mass is uniformly distributed. The Moment of Inertia of the element is equal to the Moment of Inertia of the entire Disk minus the Moment of Inertia of the Hole, that is to say:

I = I_{D} - I_{H} (1)

Where:

  • I_{D} - Moment of inertia of the Disk.
  • I_{H} - Moment of inertia of the Hole.

Then, this formula is expanded as follows:

I = \frac{1}{2}\cdot M\cdot R^{2} - \frac{1}{2}\cdot m\cdot \left(\frac{1}{2}\cdot R^{2} \right) (1b)

Dimensionally speaking, Mass is directly proportional to the square of the Radius, then we derive the following expression for the Mass removed by the Hole (m):

\frac{m}{M} = \frac{R^{2}}{4\cdot R^{2}}

m = \frac{1}{2}\cdot M

And the resulting equation is:

I = \frac{1}{2}\cdot M\cdot R^{2} -\frac{1}{2}\cdot \left(\frac{1}{4}\cdot M \right) \cdot \left(\frac{1}{4}\cdot R^{2} \right)

I = \frac{1}{2} \cdot M\cdot R^{2} - \frac{1}{32}\cdot M\cdot R^{2}

I = \frac{15}{32}\cdot M\cdot R^{2}

The moment of inertia of the Disc is represented by I = \frac{15}{32}\cdot M\cdot R^{2}. (Correct answer: A)

Please see this question related to Moments of Inertia: brainly.com/question/15246709

5 0
2 years ago
Calculate the magnitude and direction of the electric field 2.0 m from a long wire that is charged uniformly at λ = 4.0 × 10-6 C
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∫E*dr=Q inside/εo  Q inside is given by: λ*L then,

E*2*π*r*L=λ*L/εo

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6 0
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3 0
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