Why do you think the temperature does not change much during a phase change?
2 answers:
Answer:
<em>By </em> <em>the </em> <em>there </em> <em>is </em> <em>no </em> <em>change</em> <em> </em> <em>in </em> <em>the </em> <em>temperature</em> <em> </em> <em>until </em> <em>the </em> <em>phase </em> <em>change </em> <em>is </em> <em>complete.</em> <em> </em> <em>It </em> <em>is </em> <em>tha</em> <em>t</em> <em> </em> <em>during</em> <em> </em> <em>the </em> <em>phase </em> <em>change </em> <em>the </em> <em>energy </em> <em>supplied </em> <em>is </em> <em>used </em> <em>only </em> <em>to </em> <em>seperate </em> <em>the </em> <em>molecules </em> <em>no </em> <em>part </em> <em>of </em> <em>it </em> <em>is </em> <em>used </em> <em>to </em> <em>increase </em> <em>the </em> <em>relating </em> <em>to </em> <em>a </em> <em>result </em> <em>from </em> <em>the </em> <em>motion </em> <em>energy</em> <em> </em> <em>of </em> <em>the </em> <em>molecules </em> <em>so </em> <em>it's </em> <em>temperature</em> <em> </em> <em>will </em> <em>not </em> <em>rise </em> <em>since </em> <em>the </em> <em>relating</em> <em> to</em> <em> a</em> <em> </em> <em>result</em> <em> </em> <em>from</em> <em> the</em> <em> </em> <em>motion </em> <em>energy </em> <em>of </em> <em>molecules </em> <em>remains </em> <em>the </em> <em>same </em> <em>.</em>
<em><u>I </u></em> <em><u>hope </u></em> <em><u>this </u></em> <em><u>might </u></em> <em><u>help </u></em> <em><u>u</u></em> <em> </em>
Answer:
It depends on where the temperature is dropping, in which body so to speak. Generally, the temperature adapts to the two bodies, for example if a hot piece of metal meets a cold one, the two will continue until they are at an equal temperature, an intermediate temperature.
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