) A steel guitar string with a diameter of 1.00 mm is stretched between supports 80.0 cm apart. The temperature is 0.0°C. (a) Fi
nd the mass per unit length of this string. (Use the value 7.86 x103 for the density (b) The fundamental frequency of transverse oscillations of the string is 200 Hz. What is the tension in the string? (c) If the temperature is raised to 30.0°C, find the resulting values of the tension and the fundamental frequency. Assume that both the Young’s modulus and the average coefficient of expansion have constant values between 0.0°C and 30.0°C.
1 answer:
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Answer:
The wave speed of the sound wave is 900 .
Explanation:
Wavelength is the minimum distance between two successive points on the wave that are in the same state of vibration. It is expressed in units of length (m).
Frequency is the number of vibrations that occur in a unit of time. Its unit is s⁻¹ or hertz (Hz).
The propagation velocity is the speed with which the wave propagates in the medium, that is, it is the magnitude that measures the speed at which the wave disturbance propagates along its displacement. Relate the wavelength (λ) and the frequency (f) inversely proportional using the following equation: v = f * λ.
In this case:
- f= 500 Hz
- λ= 1.8 m
Replacing:
v= 500 Hz* 1.8 m
v= 900
<u><em>The wave speed of the sound wave is 900 </em></u><u><em>.</em></u>