<h3><u>Answer:-</u></h3>
3. <u>Proton</u> is the subatomic particle which accounts for most of an atom's mass.
4. <u>Electrons</u> are the subatomic particle which accounts for most of atoms volume.
Answer:
2.30 × 10⁻⁶ M
Explanation:
Step 1: Given data
Concentration of Mg²⁺ ([Mg²⁺]): 0.039 M
Solubility product constant of Mg(OH)₂ (Ksp): 2.06 × 10⁻¹³
Step 2: Write the reaction for the solution of Mg(OH)₂
Mg(OH)₂(s) ⇄ Mg²⁺(aq) + 2 OH⁻(aq)
Step 3: Calculate the minimum [OH⁻] required to trigger the precipitation of Mg²⁺ as Mg(OH)₂
We will use the following expression.
Ksp = 2.06 × 10⁻¹³ = [Mg²⁺] × [OH⁻]²
[OH⁻] = 2.30 × 10⁻⁶ M
Ionic compounds are formed by the complete transfer of electrons between the atoms. The atom which gains electron(s) forms anion whereas loss of electron(s) results in the formation of cation. They are bonded to each other by electrostatic force of attraction between the negatively and positively charged atoms.
While writing the ionic chemical formula for binary ionic compound the rules are:
- Writing the chemical symbol of the metals and non-metals involved in the compound formation.
- The charge i.e. the absolute value of oxidation number of each metal is written on respective atoms.
- The charge i.e. the absolute value of oxidation number are cross-multiplied that is the charge of first ion becomes the subscript of second ion and vice versa.
Hence, in the writing of ionic chemical formulas, the value of each ion's charge is "crossed over" in the crossover rule.
The answer is 680L because once you balance the equation, there is 2 moles of hydrogen so you multiple the amount of hydrogen by 2.
Answer:
1 gram of H2 will be produced from 12 grams of Mg.
Explanation:
According to Stoichiometry, 0.5 moles of Mg are present. 1 mole of Mg produces 1 mole of H2, so 0.5 moles of Mg will produce 0.5 moles of H2. Multiplying molar mass of H2 i.e. 2 gram/mole with 0.5 moles, we can find the mass of H2 in grams which is 1 gram.