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mafiozo [28]
3 years ago
6

Which characteristic of a strong acid

Chemistry
1 answer:
Volgvan3 years ago
5 0

Answer:

It ionizes completely in solution

Explanation:

The main characteristics of a strong acid is that it ionizes completely in solution. A strong acid will produce hydroxonium ions in solution.

A weak acid does not ionize completely in solution. Their ionization is very small and most times, the exists in equilibrium phase with the product formed.

A weak base also ionizes partially in solution.

A weak acid does not ionize completely in a given solution and it exists in equilibrium with the product.

The actions of strong acids are usually fast.

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ehidna [41]
Use formula: Initial Pressure x Initial Volume/Initial temperature = Final pressure x Final Volume/Final Temperature => 17.15L

6 0
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How can you increase the momentum of an object?
Elena-2011 [213]
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calculate the volume that will be occupied by 350 ml of oxygen measured at 720 mm hg, when the pressure changed to 630 mm hg
likoan [24]

Answer:

406.45mL

Explanation:

The following data were obtained from the question:

V1 = 350mL

P1 = 720mmHg

P2 = 630mmHg

V2 =?

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8 0
3 years ago
Part 1: What is the final volume in milliliters when 0.730 L of a 44.8 % (m/v) solution is diluted to 23.3 % (m/v)?
Andre45 [30]

part 1 : the final volume : 1.404 L

part 2 : the initial concentration : 4.06 M

<h3>Further explanation </h3>

Dilution is the process of adding a solvent to get a more dilute solution.

The moles(n) before and after dilution are the same.

Can be formulated :

M₁V₁=M₂V₂

M₁ = Molarity of the solution before dilution  

V₁ = volume of the solution before dilution  

M₂ = Molarity of the solution after dilution  

V₂ = Molarity volume of the solution after dilution

part 1 :

M₁=44.8%

V₁=0.73 L

M₂=23.3%

\tt V_2=\dfrac{M_1.V_1}{M_2}\\\\V_2=\dfrac{44.8\times 0.73}{23.3}\\\\V_2=1.404~L

part 2 :

V₁=739 ml=0.739 L

V₂=1.5 L

M₂=2

\tt M_1=\dfrac{M_2.V_2}{V_1}\\\\M_1=\dfrac{2\times 1.5}{0.739}\\\\M_1=4.06

6 0
3 years ago
The mass lost by the positive electron should equal the mass gained by the negative electrode suggest two reasons why the result
vesna_86 [32]

Answer:

The gain in mass by the negative electrode is the same as the loss in mass by the positive electrode. So the copper deposited on the negative electrode must be the same copper ions that are lost from the positive electrode.

3 0
2 years ago
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