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myrzilka [38]
3 years ago
11

During prophase, which of the following events

Chemistry
1 answer:
alexdok [17]3 years ago
7 0

Answer:

Spindle fibers form.

DNA condenses into chromosomes.

Explanation:

Prophase is the first stage of mitosis. Mitosis produces 2 daughter cells from a parental cell.

Spindle fibers form - this is true. During prophase, the mitotic spindle forms. Later during mitosis the spindle attaches to the centromere of chromosomes and pulls them to opposite ends of the cell prior to division

DNA condenses into chromosomes.  - this is true. In the nucleus during interphase, the DNA is relatively loosely compacted. However, prior to division, the DNA is condensed into structures called chromosomes which are then paired up and distributed to the daughter cell.

Chromosomes move to opposite ends of the  cell.  - this is false. This happens during anaphase

Nuclear membrane begins to re-form. - this is false. This happens during telophase.

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A _ _ has a definite composition that will not vary
emmasim [6.3K]

Answer: Mixtures do not have the same composition, properties, and appearance throughout.

Explanation: It does not vary from sample to sample.

7 0
3 years ago
Why is Dalton credited with proposing the first atomic theory if Democritus was talking about atoms almost 2,200 years earlier?
german
Democritus *suggested* the existence of the atom, that everything was made up of tiny particles, but wasn't really able to get more specific than that. Dalton also theorized that everything was made up of indivisible particles, but went further basing his theory on actual scientific principles, such as the Law of Conservation of Mass and the Law of Constant Composition. He also said that atoms weren't created or destroyed in a chemical reaction, just rearranged.  There's more to it than that, but basically, Dalton's theory was based more on science while Democritus' theory was too general to be useful in chemical situations.
4 0
2 years ago
Read 2 more answers
Choose the aqueous solution below with the highest freezing point. These are all solutions of nonvolatile solutes and you should
GrogVix [38]

Answer:

0.200 m K3PO3

Explanation:

Let us remember that the freezing point depression is obtained from the formula;

ΔTf = Kf m i

Where;

Kf = freezing point constant

m = molality

i = Van't Hoff factor

The  Van't Hoff factor has to do with the number of particles in solution. Let us consider the  Van't Hoff factor for each specie.

0.200 m HOCH2CH2OH - 1

0.200 m Ba(NO3)2 - 3

0.200 m K3PO3 - 4

0.200 m Ca(CIO4)2 - 3

Hence, 0.200 m K3PO3 has the greatest van't Hoff factor and consequently the greatest freezing point depression.

8 0
2 years ago
The combustion of ethyne, shown below unbalance, produces heat which can be used to weld metals:
Andreyy89

Answer:

3.69 g

Explanation:

Given that:

The mass m = 325 g

The change in temperature ΔT = ( 1540 - 165)° C

= 1375 ° C

Heat capacity c_p = 0.490 J/g°C

The amount of heat required:

q = mcΔT

q =  325 × 0.490 × 1375

q = 218968.75 J

q = 218.97 kJ

The equation for the reaction is expressed as:

C_2H_{2(g)} + 5O_{2(g)} \to 2CO_{2(g)} + H_2O_{(g)}   \ \   \ \ \  \Delta H^o_{reaction} = -1544 \ kJ

Then,

1 mole of the ethyne is equal to 26 g of ethyne required for 1544 kJ heat.

Thus, for 218.97 kJ, the amount of ethyne gas required will be:

= \dfrac{26 \ g}{1544 \ kJ} \times 218.97 \ kJ

= 3.69 g

3 0
3 years ago
Which pair of formulas represents the empirical formula and the molecular formula of a compound?
AnnyKZ [126]

Answer:

CH2O and C6H12O6

Explanation:

To find an empirical formula, take a molecular formula and divide the subscript of each element by the greatest common factor of all the subscripts. In this case, the only pair that works is CH2O,C6H12O6, which can be verified by dividing the coefficients of the molecular formula by 6.

3 0
2 years ago
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