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Mars2501 [29]
4 years ago
12

The primary mirror in a reflecting telescope is a

Physics
2 answers:
katovenus [111]4 years ago
5 0

Answer: Concave mirror

Explanation: A concave mirror focus is the incoming light.

Alborosie4 years ago
3 0

Answer: Concave Mirror

Explanation:

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I need help on this question, please.
frez [133]

Answer:

|X| = 72 cm

Explanation:

We need to find the magnitude of vector X.

Vector Y = 21 cm

Vector Z = 75 cm

We know that, the magnitude of resultant vector is given by :

Z={X^2+Y^2} \\\\X^2=Z^2-Y^2\\\\X^2=(75)^2-(21)^2\\\\X=72\ cm

So, the value of magnitude of vector X is 72 cm

4 0
3 years ago
What is Newton's third law of motion? In what way could this law connect to the idea of conserving momentum?
Pachacha [2.7K]

Answer: The third law states that for every action (force) in nature there is an equal and opposite reaction.

Explanation:

if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A. Notice that the forces are exerted on different objects.

Hope this helps you! Have a good day! ^-^

6 0
3 years ago
What is the acceleration due to gravity on Mars?
Leona [35]

The acceleration of gravity on Mars is about 3.7 m/s². (b)

So anything located on the surface of Mars weighs about 38% of what it would weigh if it were on Earth.

8 0
4 years ago
In lecture, Dr. Selby used atmospheric air pressure to crush a can, by sucking the air out of it. (a) Calculate how many Newtons
Ahat [919]

Answer:

a) F1 = 1999.8 N , F2 = 4545 N ,  F3 = 2778 N , c) the cans do not collapse because the pressure is applied on both sides

Explanation:

Let's use the pressure equation

      P = F / A

Suppose we have atmospheric pressure 1.01 10⁵ Pa

Let's calculate the area of ​​the can that is a parallelepiped

Length L = 25 cm

width a = 18 cm

high h = 11 cm

Side area A = h a

      A = 11 18

      A1 = 198 10⁻⁴ m²

Lid area

     A2 = L a

     A2 = 25 18

     A2 = 450 10⁻⁴ m²

Other side area

    A3 = L h

    A3 = 25 11

    A3 = 275 10⁻⁴ m²

Now let's calculate the force on these sides

Side 1

     F1 = P * A1

     F1 = 1.01 10⁵ 198 10⁻⁴

     F1 = 1999.8 N

Side 2

    F2 = P A2

    F2 = 1.01 10⁵ 450 10⁻⁴

    F2 = 4545 N

Side 3

   F3 P A3

   F3 = 1.01 10⁵ 275 10⁻⁴

   F3 = 2778 N

We see that the force is greater on side 2 which is where the can should collapse

b) To compare the previous forces we must use the concept of density, in general the cans are made of aluminum that has a density of 2700 kg / m3

    d = m / V

    m = d * V

    V = L a h

    V = 0.25 0.18 0.11

    V = 0.00495 m3

    m = 2700 0.00495

    m = 13.4 kg

This is the maximum weight, because much of the volume we calculate is air that has a much lower density

   W = 13.4 * 9.8

   W = 131.3 N

Let's make the comparison by saying the two magnitudes

Side 1

    F1 / W = 1999.8 / 131.3

    F1 / W = 15.2

Side 2

    F2 / W = 4545 / 131.3

    F2 / W = 34.6

Side 3

   F3 / W = 2778 / 131.3

   F3 / W = 21.2

c) the cans do not collapse because the pressure is applied on both sides: outside and inside, so the net force is zero on each side.

7 0
4 years ago
Which option is a force:<br><br>A. velocity<br><br>B. acceleration<br><br>C. mass<br><br>D. weight
ehidna [41]

Answer:

D

Explanation:

Weight and force have same derived units

8 0
3 years ago
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