What is the function of the organelle labeled E in the diagram?

A battery is connected to the two ends of a conducting rod and the current through it is measured.a) Another rod, made of the sa

IceJOKER [234]

Answer:

a) - the resistance is proportional to the length of the metal

- a thicker rod, since resistance decreases with increasing area

b) The current is proportional to the area so this is the factor that is influenced by the electric field

Explanation:

a) When the rod is connected to the rod an electrical circuit described by the expression is formed

V = I R

I = V / R

The resistance of the rod is

R = ρ L / A

Where ρ is the resistivity of metal, L Longitud and A cross section.

If a higher current is measured when the other rod is connected, it implies that the resistance has decreased. To have a decrease in resistance you have two possibilities

- use a shorter rod, since the resistance is proportional to the length of the metal

- Use a thicker rod, since resistance decreases with increasing area, remember that the area of a circle is

A = π R²

Therefore, small increases in the diameter of the rod could give great changes in resistance.

b) The current is defined with the charge that crosses a surface per unit of time, when the electric field increases the electrons feel a greater force, therefore the current increases.

The charge number on a wire is

Q = q n $v_{d}$ Δt A

So up to date is

I = q n When the rod is connected to the rod an electrical circuit described by the expression is formed

V = I R

I = V / R

The resistance of the rod is

R = rho L / A

Where rho is the resistivity of metal, L e; Long and A cross section.

If a higher current is measured when the other rod is connected, it implies that the resistance has decreased. To have a decrease in resistance you have two possibilities

.- use a shorter rod, since the resistance is proportional to the length of the metal

. - Use a thicker rod, since resistance decreases with increasing area, remember that the area of a circle is

A = pi R2

Therefore, small increases in the diameter of the rod could give great changes in resistance.

.b) The current is defined with the charge that crosses a surface per unit of time, when the electric field increases the electrons feel a greater force, therefore the current increases.

The load number on a wire is

Q = q n $v_{d}$ Dt A

So current is

I = q n v_{d} A

The drag speed (v_{d}) is constant in the materials, it depends on the purity and imperfections, so a change in the length does not significantly change the current.

The current is proportional to the area so this is the factor that is influenced by the electric field

The drag speed (vd) is constant in the materials, it depends on the purity and imperfections, so a change in the length does not significantly change the current.

The current is proportional to the area so this is the factor that is influenced by the electric field

8 0

3 years ago

Light of wavelength 648.0 nm is incident on a narrow slit. The diffraction pattern is viewed on a screen 57.5 cm from the slit.

boyakko [2]

Answer:

$71.0 \mu m$

Explanation:

The formula for the single-slit diffraction is

$y=\frac{n\lambda D}{d}$

where

y is the distance of the n-minimum from the centre of the diffraction pattern

D is the distance of the screen from the slit

d is the width of the slit

$\lambda$ is the wavelength of the light

In this problem,

$\lambda=648.0 nm=6.48\cdot 10^{-7}m$

$D=57.5 cm=0.575 m$

$y=1.05 cm=0.0105 m$ , with n=2 (this is the distance of the 2nd-order minimum from the central maximum)

Solving the formula for d, we find:

$d=\frac{n\lambda D}{y}=\frac{2(6.48\cdot 10^{-7} m)(0.575 m)}{0.0105 m}=7.10\cdot 10^{-5} m= 71.0 \mu m$

6 0

3 years ago

Absolute potential difference ,due of point charge of 1C at a distance of 1 m is given by

astra-53 [7]

Answer:

$\implies U = \dfrac{kq}{r}$

$\implies U = \dfrac{9 \times {10}^{9} \times 1}{1}$

$\implies U = 9 \times {10}^{9} \: J$

3 0

3 years ago

Jack and Jill are on two different floors of their high rise office building and looking out of their respective windows. Jack s

Maru [420]

Answer:

a) speed when Jack sees the pot : 12.92 meters per second

b) height difference 163.115 meters

Explanation:

First to calculate te initial speed we use the acceleration formula:

a= v1-v0/t

Acceleration being gravity's acceleration (9.8 m/s^2)

v1 being the speed when Jill sees the pot

v0 when Jack sees it

and t the time between

Solving for v0 it would be

v1 - a*t = v0

replacing

$58 m/s - 9.8 m/s^2 *4.6 s = v0 = 12.92 m/s$

For the second question we use the position formula setting y0 and t0 as the position and time when jack sees the pot. (and setting the positive axis downward I.E. one meter below jack would be 1m not -1m)

The formula is

$y0 + v0*t + 1/2 g *t^2 = yt$

replacing

$0m + 12.92m/s* 4.6 s + 1/2 * 9.8 m/s^2 * (4.6 s)^2 = 163.115 m$

5 0

3 years ago

I need help with this

insens350 [35]

Answer:

distance = 32 kilometers

displacement = 0 kilometers

Explanation:

they traveled 15 km to and back which would mean the distance they traveled is 32 km. but the displacement would still be 0 because their starting and ending points are the same.

7 0

3 years ago