Fibroblast, White Blood Cells, Plasma.
We could take the easy way out and just say
(110 kW) x (3 hours) = 330 kilowatt hours .
But that's cheap, and hardly worth even 5 points.
If we want to talk energy, let's use the actual scientific unit of energy.
________________________________________________
" 110 kw " means 110,000 watts = 110,000 joules/second .
(3 hours) x (3600 sec/hour) = 10,800 seconds.
(110,000 joules/second) x (10,800 seconds) = 1.188 x 10⁹ Joules
That's
==> 1,188,000,000 joules
==> 1,188,000 kilojoules
==> 1,188 megajoules
==> 1.188 gigajoules
Atsa nawfulotta energy !
It goes back to that "110 kw appliance" that we started with.
That's no common ordinary household appliance. 110 kw is something like
147 horsepower. In order to bring 110 kw into your house, you'd need to
take 458 Amperes through the 240-volt line from the pole. Most houses
are limited to 100 or 200 Amperes, tops. And the TRANSFORMER on
the pole, that supplies the whole neighborhood, is probably a 50 kw unit.
Answer:
Efficiency = 30% = 0.3
Explanation:
The general formula for efficiency of a device is given as:
Efficiency = (Desired Output/ Input) * 100%
Here, in our case, we have a petrol engine as a device. So, we analyze it for the efficiency calculations. Here, we have:
Chemical Potential Energy = 1000 J
Kinetic Energy = 300 J
Heat and Sound Energy = 700 J
Now, we know that the desired output of a car or the purpose of a car is to provide Kinetic energy, while all other forms of energy such as heat and sound energies are produced as waste. And the chemical energy is provided to car as input, in form of fuel. Therefore,
Input = Chemical Potential Energy = 1000 J
Desired Output = Kinetic Energy = 300 J
Therefore,
Efficiency = (300 J/1000 J) * 100%
<u>Efficiency = 30% = 0.3</u>
Hey this is what i found on the internet
<span>
specific heat (Cp) - the heat required to raise the temperature of the unit mass of a given substance by a given amount (usually one degree)
the equation related to this theory is
</span><span>Q=m Cp </span>ΔT<span>
Where Q is the energy gained or lost from the system
m is the mass of the object
</span><span> Cp is the specific heat of the material
</span>ΔT <span>is the change in temperature</span>
