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Ad libitum [116K]
3 years ago
15

If you go outside on a hot summer day with a double scoop ice cream cone, how will the cold ice cream interact with the hot outs

ide air?
Physics
2 answers:
Anastasy [175]3 years ago
5 0

Answer:

The ice cream and the air are at a different temperature, the air temperature being higher than the ice cream temperature.

Due to this difference, the air and ice cream will tend to reach a state of equilibrium by <u>transferring energy in the form of heat</u>, which flows from the system with a higher temperature to the system with a lower temperature.

So the hot air will transfer heat to the ice cream, which will increase its temperature and will make it liquid, so the ice cream will eventually melt.

lesya [120]3 years ago
3 0
Well a simple answer would be it would start to melt because icecream is a liquid unless its frozen,just like ice.
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The awnser is B

Explanation:

I took the test.

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A student solving a physics problem for the range of a projectile has obtained the expression
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Answer:

The range of the projectile is 66.7 meters.

Explanation:

The range of a projectile is given by the following expression as :

R=\dfrac{v_o^2\ sin2\theta}{g}..............(1)

v_o=37.2\ m/s

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3 years ago
Desde el balcón de un edificio se deja caer una manzana y llega a la planta baja en 5 s. ¿Desde qué piso se dejó caer, si cada p
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Answer: 42

Explanation:

I will answer this in English.

We know that the apple needs 5 seconds to reach the ground.

Each floor of the building has a height of 2.88m.

Now, when we drop something, the only force acting on the object is the gravitational one, so the acceleration of the apple is:

a = -g

for the velocity, we integrate the acceleration over time, and as the apple is dropped, we do not have any initial velocity, so we do not have a constant in the integration:

v = -g*t

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p = (-g/2)*t^2 + H

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i will use g = 9.8m/s^2

0 = (-4.9m/s^2)*(5s)^2 + H  

H = 122.5 m

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A runner changing speed from 3 meters per second to 5 meters per second is an example of
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