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3 years ago

The area around a charged object that can exert a force on other charges objects is an electric_____.

Physics

2 answers:

Pepsi [2]3 years ago

7 0

The answer is Electric force.

lisov135 [29]3 years ago

6 0

Electric force... Hope this helps

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¿De qué altura cae un cuerpo que tarda 4 s en llegar al suelo? usar g = 10 m/s2 *

jasenka [17]

Answer:

Explanation:

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2 years ago

The acclaimed environmental book, Silent Spring, was written by this woman in 1962.

olga_2 [115]

Rachel Carson was the author of the acclaimed environmental book, Silent Spring. The book was published in 1962.
It documented the negative effect that synthetic pesticides have on the environment, specifically on birds.
This book laid bare to the American public what chemical companies indirectly contributed to the environment.
The public furor this book caused led to the reversal of the national pesticide policy, a nationwide ban on DDT for agricultural uses, and inspired the creation of the U.S. Environmental Protection Agency.

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3 years ago

Can anyone help ????

user100 [1]

Explanation:

1. serie

2.Red

3.16 ohms

I=V/R

6=V/16

V=16×6

V=96 volts

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3 years ago

SOMEONE PLEASE HELP!!

Arisa [49]

Hello!

$\large\boxed{\text{C. 7,350,000 J}}$

Use the equation:

$PE = mgh$

Where:

m = mass of the object (kg)

g = acceleration due to gravity (≈9.8 m/s)

h = height above ground (m)

Plug the given values into the equation:

PE = 7500 · 9.8 · 100

PE = 7,350,000 Joules.

7 0

2 years ago

Ron is on a Ferris wheel of radius 30 ft that turns counterclockwise at a rate of one revolution every 12 seconds. The lowest po

alexgriva [62]

Answer:

$x = 30cos\frac{\pi}{6}t$

$y = 30sin\frac{\pi}{6}t + 45$

Explanation:

1 full revolution is $2\pi.$ let \theta be the angle of Ron's position.

At t = 0. $\theta = 0$

one full revolution occurs in 12 sec, so his angle at t time is

$\theta =2\pi \frac{t}{12} = \frac{\pi}{6}t$

r is radius of circle and it is given as

$x = rcos\theta$

$y = rsin\theta$

for r = 30 sec

$x = 30cos\frac{\pi}{6}t$

$y = 30sin\frac{\pi}{6}t$

however, that is centered at (0,0) and the positioned at time t = 0 is (30,0). it is need to shift so that the start position is (30,45). it can be done by adding to y

$x = 30cos\frac{\pi}{6}t$

$y = 30sin\frac{\pi}{6}t + 45$

7 0

2 years ago