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bagirrra123 [75]
3 years ago
8

Forces are needed to make a car do which of these?

Physics
1 answer:
zalisa [80]3 years ago
8 0
All of the above.

if your car is on a steep hill it needs force to stop moving and to speed up
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A solid sphere rolls along a horizontal, smooth surface at a constant linear speed without slipping. What is the ratio between t
dsp73

Answer:

option E

Explanation:

given,

Rotational Kinetic Energy, KE_r = \dfrac{1}{2}I\omega^2

Moment of inertia of the solid,

I = \dfrac{2}{5}MR^2

\omega = \dfrac{V}{R}

now,

KE_r = \dfrac{1}{2}I\omega^2

KE_r = \dfrac{1}{2}\times \dfrac{2}{5}MR^2 (\dfrac{V}{R})^2

KE_r =\dfrac{1}{5}MV^2......(1)

transnational kinetic energy

KE_t =\dfrac{1}{2}MV^2

Total kinetic energy

KE = \dfrac{1}{2}MV^2 + \dfrac{1}{5} MV^2

KE = \dfrac{7}{10}MV^2

ratio of rotational kinetic energy to the total kinetic energy

\dfrac{KE_r}{KE_t}=\dfrac{\dfrac{1}{5}MV^2}{\dfrac{7}{10}MV^2}

\dfrac{KE_r}{KE_t}=\dfrac{2}{7}

hence, the correct answer is option E

4 0
3 years ago
1) Which of the following alternative energy sources is NOT inexhaustible?
kakasveta [241]
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A capacitor consists of a set of two parallel plates of area A separated by a distance d. This capacitor is connected to a batte
vovikov84 [41]
<h2>Answer:</h2>

(e) halved

<h2>Explanation:</h2>

The electrical enery (E) stored in a capacitor is related to its capacitance (C) and potential difference (V) as follows;

E = \frac{1}{2} x C x V^{2}   ------------------------(i)

Also, the capacitance (C) of a capacitor consisting of parallel plates is related to the area (A) of the plates and distance (d) between the plates as follows;

C = A x ε₀ / d    ------------------------(ii)

Where;

ε₀ is the permittivity of free space.

Substituting equation (ii) into equation (i) gives;

E = \frac{1}{2} x A x ε₀ / d x V^{2}  --------------------(iii)

From equation(iii)

When the potential difference (V) is constant, then the electrical energy (E) stored is <em>inversely </em>proportional to the distance between the plates. i.e

E = k / d   ----------------(iv)

Where;

k = proportionality constant = \frac{1}{2} x A x ε₀ x V^{2} (which is the product of all constants)

Therefore from equation (iv);

=> E₁ x d₁ = E₂ x d₂   ---------------------------(v)

Where;

E₁ and E₂ are the initial and final values of the electrical energy stored.

d₁ and d₂ are the initial and final values of the distance between the plates.

<em>So, when the distance is doubled, i.e.</em>

d₂ = 2 x d₁

<em>Substitute the value of d₂ into equation (v) to give;</em>

=> E₁ x d₁ = 2 x d₁ x E₂

<em>Divide through by d₁ to give;</em>

=> E₁ = 2 x E₂

<em>Make E₂ subject of the formula</em>

=> E₂ = \frac{1}{2} x E₁

Therefore, the electrical energy stored in the capacitor will be halved.

6 0
4 years ago
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