Ask question

Ask question

All categories

bagirrra123 [75]

2 years ago

8

Forces are needed to make a car do which of these?

1 answer:

zalisa [80]2 years ago

8 0

All of the above.

if your car is on a steep hill it needs force to stop moving and to speed up

You might be interested in

Which of the following is the flow of electrons through a wire or a conductor

Hatshy [7]

Wires or silver and copper

8 0

2 years ago

An object of mass 30 kg is falling in air and experiences a force due to air resistance of 50 newtons. Calcuate the acceleration

rjkz [21]

Answer:

this answer you question

6 0

2 years ago

The ability to make things happen is also called _____.

DerKrebs [107]

Force bc it says the ability to make stuff happen

3 0

2 years ago

In prokaryotic and eukaryotic cells the amount of water in the cell is kept at a steady state. The organelles

Len [333]

Answer:

A

Explanation:

It would not be C because prokaryotic cells don't have a nucleus. And if you're looking for a body in the cell that controls the nutrients and water it would be A.

3 0

2 years ago

Two planets P1 and P2 orbit around a star S in circular orbits with speeds v1 = 40.2 km/s, and v2 = 56.0 km/s respectively. If t

Readme [11.4K]

Answer: $3.66(10)^{33}kg$

Explanation:

We are told both planets describe a circular orbit around the star S. So, let's approach this problem begining with the angular velocity $\omega$ of the planet P1 with a period $T=750years=2.36(10)^{10}s$ :

$\omega=\frac{2\pi}{T}=\frac{V_{1}}{R}$ (1)

Where:

$V_{1}=40.2km/s=40200m/s$ is the velocity of planet P1

$R$ is the radius of the orbit of planet P1

Finding $R$ :

$R=\frac{V_{1}}{2\pi}T$ (2)

$R=\frac{40200m/s}{2\pi}2.36(10)^{10}s$ (3)

$R=1.5132(10)^{14}m$ (4)

On the other hand, we know the gravitational force $F$ between the star S with mass $M$ and the planet P1 with mass $m$ is:

$F=G\frac{Mm}{R^{2}}$ (5)

Where $G$ is the Gravitational Constant and its value is $6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}$

In addition, the centripetal force $F_{c}$ exerted on the planet is:

$F_{c}=\frac{m{V_{1}}^{2}}{R^{2}}$ (6)

Assuming this system is in equilibrium:

$F=F_{c}$ (7)

Substituting (5) and (6) in (7):

$G\frac{Mm}{R^{2}}=\frac{m{V_{1}}^{2}}{R^{2}}$ (8)

Finding $M$ :

$M=\frac{V^{2}R}{G}$ (9)

$M=\frac{(40200m/s)^{2}(1.5132(10)^{14}m)}{6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}}$ (10)

Finally:

$M=3.66(10)^{33}kg$ (11) This is the mass of the star S

4 0

3 years ago