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bagirrra123 [75]
2 years ago
8

Forces are needed to make a car do which of these?

Physics
1 answer:
zalisa [80]2 years ago
8 0
All of the above.

if your car is on a steep hill it needs force to stop moving and to speed up
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8 points
Lunna [17]
The pilot might be correct (I think), because, if the gravity of the planet is strong, then the planet’s gravity will pull the spaceship into its orbit, so the engines don’t need to be on for the ship to get pushed toward the planet.
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3 years ago
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A student connects a 1 hp motor to a bicycle. How much time will it take for the bicycle to accelerate from rest to a speed of 5
bija089 [108]

Answer:

t=2s

Explanation:

The definition of power is:

P=\frac{W}{t}

And the work-energy theorem states that:

W=\Delta K

Since the movement starts from rest, we have that:

\Delta K=\frac{mv_f^2}{2}-\frac{mv_0^2}{2}=\frac{mv_f^2}{2}

And putting all together:

P=\frac{mv_f^2}{2t}

Since we want the time taken:

t=\frac{mv_f^2}{2P}

Which for our values is:

t=\frac{(120kg)(5m/s)^2}{2(746W)}=2s

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3 years ago
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What two gases probably dominated precambrian earth's atmosphere?
galben [10]
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8 0
3 years ago
When a 2.40-kg object is hung vertically on a certain light spring described by Hooke's law, the spring stretches 2.92 cm.(a) Wh
Anastasy [175]

Answer:

805.48N/m

Explanation:

According to Hookes law

F = Ke

F is the force = mg

F = 2.4×9.8 = 23.52N

e is the extension = 2.92cm = 0.0292m

Force constant K = F/e

K = 23.52/0.0292

K = 805.48N/m

Hence the force constant of the spring is 805.48N/m

3 0
2 years ago
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-- As she lands on the air mattress, her momentum is (m v)

Momentum = (60 kg) (5 m/s down) = 300 kg-m/s down

-- As she leaves it after the bounce,

Momentum = (60 kg) (1 m/s up) = 60 kg-m/s up

-- The impulse (change in momentum) is

Change = (60 kg-m/s up) - (300 kg-m/s down)

Magnitude of the change = <em>360 km-m/s </em>

The direction of the change is <em>up /\ </em>.

8 0
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