3 years ago

What is the most important force in astronomy?

Physics

1 answer:

CaHeK987 [17]3 years ago

4 0

This is probably gravity because without gravity, everything would just be some hot dust floating through space

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A car advertisement states that a certain car that Emily Miller love can accelerate from rest to 70km/h in 7 seconds. Fine the c

alex41 [277]

Average acceleration = (change in speed) / (time for the change)

   = (70 km/hour) / (7 seconds)

   =    10 km/hr-sec .

That's a valid unit of acceleration ... [ length / time² ] ...
but it's so clunky that we can't relate to it. We usually
want to see acceleration in m/s² . So I'll convert this
answer to the more conventional unit.

   (10 km/hr-sec) · (1,000 m / 1 km) · (1 hr / 3,600 sec)

   = (10 · 1,000 · 1) / (1 · 3,600) m/s²

   = 2.78 m/s² ( about 0.28 G )

5 0

2 years ago

you are running out and the first mike takes 10 minutes the second mile takes you 20 minutes this is an example of

4vir4ik [10]

Answer:

??????

Explanation:

4 0

2 years ago

Read 2 more answers

A 110 kg ice hockey player skates at 3.0 m/s toward a railing at the edge of the ice and then stops himself by grasping the rail

velikii [3]

Answer:

Δ KE = -495 J

Explanation:

given,

mass of the ice hockey player = 110 Kg

initial speed = 3 m/s

final speed = 0 m/s

distance, d = 0.3 m

change in kinetic energy

$\Delta K E = \dfrac{1}{2}mv_f^2 - \dfrac{1}{2}mv_i^2$

$\Delta K E = \dfrac{1}{2}mv(0)^2 - \dfrac{1}{2}\times 110\times 3^2$

Δ KE = -495 J

Hence, the change in kinetic energy is equal to Δ KE = -495 J

7 0

2 years ago

g Determine the magnetic field midway between two long straight wires 2.0 cm apart in terms of the current I in one when the oth

MrMuchimi

Answer:

$B_{net}$ = $(2\times 10^{-5}T/A).(I-25A)$

Explanation:

Given :

the distance between the two wires is = 2 cm

= 0.02 m

Current in one of the wire, I = 25 A

Now we know that, when the direction of the current is same that is in one direction , the magnetic field at the mid point in between the two wires will oppose each other.

Therefore we know that

$B_{net}$ = $\frac{\mu _{o}\times I_{1}}{2\pi r_{1}}-\frac{\mu _{o}\times I_{2}}{2\pi r_{2}}$

= $\frac{(4\pi \times 10^{-7}T.m/A)}{2\pi (1\times 10^{-2}m)}\times (I-25A)$

= $(2\times 10^{-5}T/A).(I-25A)$

4 0

2 years ago

On a position vs. time graph for an object, a horizontal line segment indicates that the object is(1 point)

babunello [35]

Answer:

moving at a constant rate. (could be zero m/s)

7 0

1 year ago