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4 years ago

What is the most important force in astronomy?

Physics

1 answer:

CaHeK987 [17]4 years ago

4 0

This is probably gravity because without gravity, everything would just be some hot dust floating through space

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What is the relationship between thermal energy and temperature?

poizon [28]

As the air becomes warmer, heat is transferred between molecules and kineticenergy is created which produces thermal energy. As the molecules move faster to transfer heat, the temperature also increases.

6 0

3 years ago

Note: Plagiarism will be reported

iren [92.7K]

Y no me han dicho que me ha dado un teléfono y me ha dicho la policía que han dado la cara para la que ha sido un policía que han dicho nada que no se han dado cuenta de

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3 years ago

Read 2 more answers

A car has the velocity of 2.35 after 4.67 it's velocity is 9.89 what is the average acceleration

kiruha [24]

Average acceleration = (change in speed) / (time for the change) .

Change in speed = (ending speed) - (beginning speed)

=  (9.89 miles/hour) - (2.35 yards/second) = 26,839.2 ft/hr

Acceleration = (26,839.2 ft/hr) / (4.67 days) = 2,873.58 inch/hour²

6 0

3 years ago

A 70.0-kg person throws a 0.0430-kg snowball forward with a ground speed of 32.0 m/s. A second person, with a mass of 58.5 kg, c

Aleks04 [339]

Answer:

The velocities of the skaters are $v_{1} = 3.280\,\frac{m}{s}$ and $v_{2} = 0.024\,\frac{m}{s}$ , respectively.

Explanation:

Each skater is not under the influence of external forces during process, so that Principle of Momentum Conservation can be used on each skater:

First skater

$m_{1} \cdot v_{1, o} = m_{1} \cdot v_{1} + m_{b}\cdot v_{b}$ (1)

Second skater

$m_{b}\cdot v_{b} = (m_{2}+m_{b})\cdot v_{2}$ (2)

Where:

$m_{1}$ - Mass of the first skater, in kilograms.

$m_{2}$ - Mass of the second skater, in kilograms.

$v_{1,o}$ - Initial velocity of the first skater, in meters per second.

$v_{1}$ - Final velocity of the first skater, in meters per second.

$v_{b}$ - Launch velocity of the meter, in meters per second.

$v_{2}$ - Final velocity of the second skater, in meters per second.

If we know that $m_{1} = 70\,kg$ , $m_{b} = 0.043\,kg$ , $v_{b} = 32\,\frac{m}{s}$ , $m_{2} = 58.5\,kg$ and $v_{1,o} = 3.30\,\frac{m}{s}$ , then the velocities of the two people after the snowball is exchanged is:

By (1):

$m_{1} \cdot v_{1, o} = m_{1} \cdot v_{1} + m_{b}\cdot v_{b}$

$m_{1}\cdot v_{1,o} - m_{b}\cdot v_{b} = m_{1}\cdot v_{1}$

$v_{1} = v_{1,o} - \left(\frac{m_{b}}{m_{1}} \right)\cdot v_{b}$

$v_{1} = 3.30\,\frac{m}{s} - \left(\frac{0.043\,kg}{70\,kg}\right)\cdot \left(32\,\frac{m}{s} \right)$

$v_{1} = 3.280\,\frac{m}{s}$

By (2):

$m_{b}\cdot v_{b} = (m_{2}+m_{b})\cdot v_{2}$

$v_{2} = \frac{m_{b}\cdot v_{b}}{m_{2}+m_{b}}$

$v_{2} = \frac{(0.043\,kg)\cdot \left(32\,\frac{m}{s} \right)}{58.5\,kg + 0.043\,kg}$

$v_{2} = 0.024\,\frac{m}{s}$

5 0

3 years ago

A scientist conducting a field investigation records measurements of very low pressure and high relative humidity at the top of

Ivan

Answer:

Please find the answer in the explanation

Explanation:

Given that a scientist conducting a field investigation records measurements of very low pressure and high relative humidity at the top of a mountain.

Since a weather map indicates that a warm front is approaching the mountain, according to the conventional current, the warm front is approaching because the weather must have been in higher relative humidity in cool air.

The warm front is approaching to replace it so that the cool air can conventionally replace the warmth air too.

The condition the scientists will most likely observe at the top of the mountain will be high relative humidity.

5 0

4 years ago