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Naddik [55]
1 year ago
7

A polar jet is a belt of winds about 600 miles wide, flowing as fast as _________

Physics
1 answer:
maks197457 [2]1 year ago
5 0

A polar jet is a belt of winds about 600 miles wide, flowing as fast as 400km/hr in its central "core".

The wind speeds are greatest where temperature differences between air masses are greatest, and often exceed 92 km/h . Speeds of 400 km/h  have been measured.One factor that contributes to the creation of a concentrated polar jet is the undercutting of sub-tropical air masses by the more dense polar air masses at the polar front. This causes a sharp north-south pressure (south-north potential vorticity) gradient in the horizontal plane, an effect which is most significant during double Rossby wave breaking events.

At high altitudes, lack of friction allows air to respond freely to the steep pressure gradient with low pressure at high altitude over the pole. This results in the formation of planetary wind circulations that experience a strong Coriolis deflection and thus can be considered 'quasi-geostrophic'. The polar front jet stream is closely linked to the frontogenesis process in midlatitudes, as the acceleration/deceleration of the air flow induces areas of low/high pressure respectively, which link to the formation of cyclones and anticyclones along the polar front in a relatively narrow region.

Learn more about jet streams here:

brainly.com/question/248501

#SPJ4

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Which element makes up earth's atmosphere?
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7 0
3 years ago
The large blade of a helicopter is rotating in a horizontal circle. The length of the blade is 7.17 m, measured from its tip to
gayaneshka [121]

Answer:

1.789

Explanation:

let the tangential velocity at the tip of the blade (7.17m from center) be V₁ and the tangential velocity at 4.01 be V₂.

recall that tangential velocity can be related to angular velocity, ω by the following relationship:

V = rω, where V is the tangential velocity, ω is angular velocity and r = radius.

rearranging, we get

ω = V/r

We also know that at any point in the rotation, even though the tangential velocity at 7.17m radius (V₁)   will be different from the tangential velocity at 4.01m radius  (V₂), their angular velocity will be the same, hence we can equate:

ω₁ = ω₂, or

V₁/r₁ = V₂/r₂ (rearranging)

V₁/V₂ = r₁/r₂ -----(eq 1)

We also know that centripetal acceleration can be expressed in terms of tangential velocity and radius, i.e

a =V²/r

to find the ratio of the centripetal acceleration at the tip and at r=4.01m

a₁/a₂ = (V₁²/r₁)   / ( V₂² / r₂)   (rearranging & simplify)

=  (V₁/V₂)² (r₂ / r₁)   (substituting eq1 into equation)

=  (r₁/r₂)²(r₂ / r₁)  (simplifying)

= (r₁/r₂)    (substituting r₁=7.17 and r₂=4.01)

= 7.17 / 4.01

= 1.789

7 0
4 years ago
Polarized light is incident on three polarizing filters in a row. The initial intensity of the light is 4 W/m^2. The first filte
DiKsa [7]

Answer:

45°

Explanation:

I = Polarized light after 3 filter = 0.5 W/m²

I_0 = Initial light intensity = 4 W/m²

The intensity of polarized light is given by

I=I_0cos^2Acos^245cos^245\\\Rightarrow A=cos^{-1}\sqrt{\dfrac{I}{I_0cos^245cos^245}}\\\Rightarrow A=cos^{-1}\sqrt{\dfrac{0.5}{4\times cos^245\times cos^245}}\\\Rightarrow A=45^{\circ}

Hence, the angle relative to the vertical was the light initially polarized is 45°

4 0
3 years ago
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