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sergey [27]
3 years ago
14

What is the average velocity of the car from t=5 seconds to t=12 seconds?

Physics
1 answer:
Debora [2.8K]3 years ago
4 0

The question is not complete

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a person dives off the edge of aa cliff 33m above the surface of the sea. assuming that air resistance is negligible, how long d
USPshnik [31]

Answer:

The time is t = 2.595 \  s

The speed is v = 25.43 \ m/s

Explanation:

From the question we are told that

    The height of the cliff is  h =  33 \  m

 Generally from kinematic equation we have that

       h  =  ut + \frac{1}{2} gt^2

before the jump the persons initial velocity is  u =  0 m/s

 So

        33   =  0 * t + \frac{1}{2} 9.8 * t^2

=>      t = 2.595 \  s

Generally from kinematic equation

     v= u + gt

=>  v= 0 + 9.8 * 2.595

=>  v = 25.43 \ m/s

3 0
3 years ago
Which of the following will increase if the voltage in a circuit is increased?A.The diameter of the wire.B.Resistance.C.Power.D.
PIT_PIT [208]

Answer:

I really don't know. I think it's E.Current

sorry if I'm wrong

4 0
3 years ago
Read 2 more answers
Which region of a longitudinal wave is this?
ipn [44]
I think the correct answer is is D.
8 0
2 years ago
Help me asap and answer correctly!!!! Only answer if you know
dezoksy [38]

Answer:

B and D (Chicken and Turkey)

Explanation:

Looking at the table, we can see that chicken and turkey have an identical data set.

Good luck! Hope this helped!

7 0
2 years ago
Read 2 more answers
New 5G networks utilize millimeter-wave radiation. Millimeter-wave radiation refers to electromagnetic waves with frequencies in
seraphim [82]

Answer:

It corresponds to 1mm-10 mm range.

Explanation:

  • Electromagnetic waves (such as the millimeter-wave radiation) travel at the speed of light, which is 3*10⁸ m/s in free space.
  • As in any wave, there exists a fixed relationship between speed, frequency and wavelength, as follows:

        v = \lambda * f  (1)

  • Replacing v= c=3*10⁸ m/s, and the extreme values of f (which are givens), in (1) and solving for λ, we can get the free-space wavelengths that correspond to the 30-300 GHz range, as follows:

       \lambda_{low} = \frac{c}{f_{high}}  = \frac{3e8m/s}{300e9Hz} = 1 mm (2)

      \lambda_{high} = \frac{c}{f_{low}}  = \frac{3e8m/s}{30e9Hz} = 10 mm (3)

4 0
2 years ago
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