1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alecsey [184]
3 years ago
11

Unit processes in charge of smelting​

Chemistry
1 answer:
Svet_ta [14]3 years ago
8 0

Answer:

Smelting, process by which a metal is obtained, either as the element or as a simple compound, from its ore by heating beyond the melting point, ordinarily in the presence of oxidizing agents, such as air, or reducing agents, such as coke.

Hope I helped!

Explanation:

You might be interested in
How do dipole-dipole forces affect the melting and boiling points of substances?
RideAnS [48]
Vvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvv
6 0
3 years ago
How do you predict a reaction outcome for Ni(s) + H2O(L)?
ElenaW [278]

Answer:

Ni(s) + H₂O(l) -------------> [Ni(H₂O)₆]²⁺

Explanation:

Data Given:

Reactants:

Ni(s) + H₂O(l)

Product = ?

Solution:

Names of the Reactants

Ni = Nickel

H₂O = water

Reaction:

Normally nickel directly does not react with water under normal condition. But indirectly in acidic or neutral condition it form complex ion.

For this it first dissolve slowly in dilute acid, in this reaction it liberate Ni²⁺ ions these nickel ions form light green complex ions in aqueous solution.

              Ni(s) + H₂SO₄(aq) -------> Ni²⁺(aq) + SO₄²⁻(aq) + H₂

This is a type of complex formation in which Nickel react with water and produced a light green color new complex ion or product.

Complete reaction is as under

                  Ni(s) + H₂O(l) -------------> [Ni(H₂O)₆]²⁺

Balance Reaction:

                   Ni(s) + 6 H₂O(l) -------------> [Ni(H₂O)₆]²⁺

So.

by this reaction one product is formed that is [Ni(H₂O)₆]²⁺ named as hexaqua nickel ion

7 0
3 years ago
Write the net cell equation for this electrochemical cell. Phases are optional. Do not include the concentrations. Co ( s ) ∣ ∣
Tatiana [17]

Answer: The overall equation will be Co(s)+2Ag^+(aq)\rightarrow Co^{2+}(aq)+Ag(s)

Explanation:

The representation is given by writing the anode on left hand side followed by its ion with its molar concentration. It is followed by a salt bridge. Then the cathodic ion with its molar concentration is written and then the cathode.

Oxidation reaction is defined as the reaction in which a substance looses its electrons. The oxidation state of the substance increases.

Anode : Co(s)\rightarrow Co^{2+}(aq)+2e^{-}

Reduction reaction is defined as the reaction in which a substance gains electrons. The oxidation state of the substance gets reduced.

Cathode : Ag^+(aq)+e^{-1}\rightarrow Ag(s)  \times 2

The number of electrons lost must be equal to the number of electrons gained , thus overall equation will be :

Co(s)+2Ag^+(aq)\rightarrow Co^{2+}(aq)+Ag(s)

5 0
3 years ago
At a certain temperature, 0.800 mol SO 3 is placed in a 1.50 L container. 2 SO 3 ( g ) − ⇀ ↽ − 2 SO 2 ( g ) + O 2 ( g ) At equil
Elanso [62]

Answer : The value of equilibrium constant (K) is, 0.004

Explanation :

First we have to calculate the concentration of SO_3\text{ and }O_2

\text{Concentration of }SO_3=\frac{\text{Moles of }SO_3}{\text{Volume of solution}}=\frac{0.800mol}{1.50L}=1.2M

and,

\text{Concentration of }O_2=\frac{\text{Moles of }O_2}{\text{Volume of solution}}=\frac{0.150mol}{1.50L}=0.1M

Now we have to calculate the value of equilibrium constant (K).

The given chemical reaction is:

                       2SO_3(g)\rightarrow 2SO_2(g)+O_2(g)

Initial conc.       1.2             0               0

At eqm.          (1.2-2x)        2x               x

As we are given:

Concentration of O_2 at equilibrium = x = 0.1 M

The expression for equilibrium constant is:

K_c=\frac{[SO_2]^2[O_2]}{[SO_3]^2}

Now put all the given values in this expression, we get:

K_c=\frac{(2x)^2\times (x)}{(1.2-2x)^2}

K_c=\frac{(2\times 0.1)^2\times (0.1)}{(1.2-2\times 0.1)^2}

K_c=0.004

Thus, the value of equilibrium constant (K) is, 0.004

3 0
4 years ago
Which of the following is equal to 2.3 cm3?
Leya [2.2K]
The answer is the second one 2.3 X 10-3 dm3
4 0
4 years ago
Other questions:
  • 100 PNTS PLZ ANSWER ASAP PLZ The masses of a sample of hydrogen gas and a sample of helium gas are the same: 1 g. The density of
    15·2 answers
  • What is the ratio of the density of a substance to the density of a standard?
    13·1 answer
  • The amount of matter in an object is called _____. <br> gravity <br> mass <br> volume <br> weight
    6·2 answers
  • Compare the components that make up the windsurfer, his board, and his surroundings.
    15·2 answers
  • Air is about 78% nitrogen gas (N2) by mass. The molar mass of nitrogen gas is 28.0 g/mol. A 100.0-g sample of air contains how m
    11·2 answers
  • Scientific theories are usually
    7·2 answers
  • what is the main 'impurity' collected with the oil in distillation. PLEASE HELP IM IN END OF YEAR EXAM. II WILL GIVE BRAINLIEST
    5·1 answer
  • Container A contains 10.0 g of liquid isopropyl alcohol which has a latent heat of vaporization of 732 J/g. Container B contains
    5·1 answer
  • Why should you wear light colored clothes on a light day?
    13·1 answer
  • If the moon is full on January 16, on approximately what date will it be full in February?
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!