Answer:
V(average)=6.37 V
Explanation:
Given Data
Peak Voltage=10V
Frequency=10 kHZ
To Find
Average Voltage
Solution
For this first we need to find Voltage peak to peak
So
Voltage (peak to peak)= 2× voltage peak
Voltage (peak to peak)= 2×10
Voltage (peak to peak)= 20 V
Now from Voltage (peak to peak) formula we can find the Average Voltage
So
Voltage (peak to peak)=π×V(average)
V(average)=Voltage (peak to peak)/π
V(average)=20/3.14
V(average)=6.37 V
A SWITCH. IT controls the flow of electrons in a circuit
An exfoliation dome is a geological structure wherein it is primarily when the overburden of a surface gets removed by erosion, thus leading to rock relaxation. In addition, the term would be best applied to the national landmark of Yosemite National Park wherein the place has one of the best waterfalls in California.
a =12miles
b =10miles
ab =2miles
Explanation:
at first the car is drown out of dealership and went 10 miles east and then 8 miles south
then your friend drives 8 miles west and 6 miles north.
then the distance it flies to get back to dealership is
10²+8 ²=12miles
8²+6²=10miles
12-10= 2 miles
Answer:
F_net = 26.512 N
Explanation:
Given:
Q_a = 3.06 * 10^(-4 ) C
Q_b = -5.7 * 10^(-4 ) C
Q_c = 1.08 * 10^(-4 ) C
R_ac = 3 m
R_bc = sqrt (3^2 + 4^2) = 5m
k = 8.99 * 10^9
Coulomb's Law:
F_i = k * Q_i * Q_j / R_ij^2
Compute F_ac and F_bc :
F_ac = k * Q_a * Q_c / R^2_ac
F_ac = 8.99 * 10^9* ( 3.06 * 10^(-4 ))* (1.08 * 10^(-4 )) / 3^2
F_ac = 33.01128 N
F_bc = k * Q_b * Q_c / R^2_bc
F_bc = 8.99 * 10^9* ( 5.7 * 10^(-4 ))* (1.08 * 10^(-4 )) / 5^2
F_bc = - 22.137 N
Angle a is subtended between F_bc and y axis @ C
cos(a) = 3 / 5
sin (a) = 4 / 5
Compute F_net:
F_net = sqrt (F_x ^2 + F_y ^2)
F_x = sum of forces in x direction:
F_x = F_bc*sin(a) = 22.137*(4/5) = 17.71 N
F_y = sum of forces in y direction:
F_y = - F_bc*cos(a) + F_ac = - 22.137*(3/5) + 33.01128 = 19.72908 N
F_net = sqrt (17.71 ^2 + 19.72908 ^2) = 26.5119 N
Answer: F_net = 26.512 N
