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Airida [17]
3 years ago
6

It's five miles from Tim's house to Rita's house. Roughly how long is this distance in feet?

Physics
2 answers:
Ber [7]3 years ago
5 0
The answer is 26400
sergey [27]3 years ago
3 0

Answer:

26400 ft

Explanation:

that would be my answer

hope this helps!!! :)

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Energy travels with sound waves.
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When temperature and pressure are applied to sedimentary and igneous rock?
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Igneous rock

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6 0
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8. Before leaving the ground an airplane traveling with constant acceleration makes a run on the
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2 years ago
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a lemming running 2.87 m/s runs off a horizontal cliff. It lands in the water 5.32 m from the base of the cliff. How high was th
Vlad1618 [11]
Looking at the scenario, you can tell that this is a Type 1 Projectile, or a horizontal projectile. You would need a couple of things before you can solve this problem.

First you need to take a look at your given:

Vix = 2.87 m/s (Horizontal velocity)
dx = 5.32m (Horizontal distance)

What you need is your vertical distance or your height. The standard formula for projectile displacement is:
d = vit +  \frac{1}{2}gt^{2}

Where:
vi = initial velocity
g = Acceleration due to gravity = 9.8m/s^2
t = time

To specifically get the vertical distance you just need to put in the y-components. Now remember that initially, for a horizontal projectile, there is not vertical movement, only forward. So your vi = om/s which will leave you with the equation:

dy=viyt +  \frac{1}{2}gt^{2} 
dy=(0m/s)t + \frac{1}{2}gt^{2} 
dy=\frac{1}{2}gt^{2} 

Your new formula would then be:
dy=\frac{1}{2}gt^{2} 

But if you look at your problem, you can see that there is no time given. With what was given to you, you can solve it by deriving it from the x component formula:

dx=vixt

Plug in what you know and solve for what you don't know. 
dx=vixt
5.32m=(2.87m/s)t
\frac{5.32m}{2.87m/s}=t
1.85s=t

Your time is then 1.85s.

Now that you know the time, you can now solve for your vertical distance/displacement:

dy=\frac{1}{2}gt^{2}
dy=\frac{1}{2}(9.8m/s^{2}(1.85s)^{2} 
dy=\frac{1}{2}(9.8m/s^{2}(1.85s)^{2} 
dy=16.77m 
 

The cliff was then 16.77m high. 
5 0
3 years ago
The Cleveland City Cable Railway had a 14-foot-diameter pulley to drive the cable. In order to keep the cable cars moving at a l
dsp73

Answer:

13.94 rpm

Explanation:

Given that,

The diameter of the pulley, d = 14 foot

Radius, r = 7 foot

The linear velocity of the pulley, v = 14 mph = 20.53 ft/s

We need to find the angular velocity in rpm.

We know that, the relation between the linear velocity and the angular velocity is as follows :

v=r\omega\\\\\omega=\dfrac{v}{r}\\\\\omega=\dfrac{20.53}{14}\\\\\omega=1.46\ rad/s

or

\omega=13.94\ rpm

So, the angular velocity of the pulley is 13.94 rpm.

4 0
2 years ago
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