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RUDIKE [14]
3 years ago
13

What trend do you note for the atomic radii of the third period?

Chemistry
2 answers:
Natasha_Volkova [10]3 years ago
6 0

。☆✼★ ━━━━━━━━━━━━━━━  ☾

As you move across the period, the atomic radii decreases.

This is because of an increase in the number of protons (and electrons) and therefore, an increase in the nuclear charge.

Have A Nice Day ❤

Stay Brainly! ヅ

- Ally ✧

。☆✼★ ━━━━━━━━━━━━━━━━  ☾

Law Incorporation [45]3 years ago
5 0

Answer:

The atomic radii decreases from left (sodium) to right (Argon).

Explanation:

The number of  positive protons in the nucleus increases so the pull on the electrons increases and this decreases the radius.

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5.00 x  1011/s = 5.05500kilohertz
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The AE of a system that releases 12.4 J of heat and does 4.2 J of work on its surroundings It is_______ jA. 16.6 B. 12.4 C. 4.2
andre [41]

ANSWER

EXPLANATION

Given that

The energy released by the system is 12.4J

Work done on the surrounding is 4.2J

Follow the steps below to find the change in energy

In the given data, energy is said to be released to the surroundings

Recall, that exothermic reaction is a type of reaction in which heat is released to the surroundings. Hence, change in enthalpy is negative

Step 1; Write the formula for calculating change in energy

\Delta E\text{ }=\text{ q }+\text{ w}

Since heat is released to the surrounding, then q = -12J

Recall, that work done by the system on the surroundings is always negative

Hence, w = -4.2J

Step 2; Substitute the given data into the formula in step 1

\begin{gathered} \text{  }\Delta E\text{ = q + w} \\ \text{  }\Delta E\text{ }=\text{ -12.4 }+\text{ \lparen-4.2\rparen} \\ \text{  }\Delta E\text{ = -12.4 - 4.2} \\ \text{  }\Delta E\text{ }=\text{ -16.6J} \end{gathered}

Therefore, the change i

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Explain why there is a need for an universal system of measurement. Why is the metric system of measurement convenient to use
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Explanation:

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4 0
3 years ago
2N2 + O2 -------> 2 N2O
notka56 [123]

Answer:

Explanation:

Given data:

Mass of N₂ = 48.7 g

Moles of N₂ = ?

Molecules of N₂ = ?

Mass of N₂O = ?

Moles of N₂O = ?

Atoms of N₂O = ?

Solution:

Chemical equation:

2N₂ + O₂  →  2N₂O

Number of moles of N₂:

Number of moles = mass/ molar mass

Number of moles = 48.7 g / 28 g/mol

Number of moles = 1.74 mol

Number of molecules of N₂:

1 mole = 6.022 × 10²³ molecules

1.74 mol×  6.022 × 10²³ molecules/1 mol

10.5  × 10²³ molecules

Now we will compare the moles of N₂ with N₂O from balance chemical equation:

                 N₂             :           N₂O

                  2             :             2

               1.74            :           1.74

Moles of N₂O:  

1.74 mol

Mass of N₂O:

Mass = number of moles × molar mass

Mass =  1.74 mol ×  44 g/mol

Mass = 76.56 g

8 0
3 years ago
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