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How many molecules does 88 grams CO2 contain? A) 1.2 X 1024 B) 1.8 X 1024 C) 3.0 X 1023 D) 6.0 X 1023

mylen [45]

Hey there!:

Molar mass CO2 = 44.01 g/mol

44.01 g CO2 ------------------- 6.02*10²² molecules CO2

88 g CO2 ------------------------ y

y = 88 * ( 6.02*10²² ) / 44.01

y = 5.29*10²⁵ / 44.01

y = 1.2 * 10²⁴ molecules of CO2

Answer A

Hope that helps!

7 0

3 years ago

9.The industrial preparation of hydrogen gas from water gas is referred to as

natima [27]

Answer: Bosch process

Explanation:

Bosch process is an industrial process for the manufacture of H2. This proces uses cheap raw materials( water and coke) to generate water gas which is mixed with water in the presence of a catalyst(iron(II) oxide or chromium(iii) oxide) to generate H2

6 0

4 years ago

Commercial products commonly report concentration in terms of "percentage." Using this

Stella [2.4K]

The answer to the question is 0.8055 as the answer should not include units in it.

Molarity (M) = n/v

n = moles of solute

v = liters of solution

According to question

1% solution → 1 gram of solute for 100 milliliters of solution

2% solution → 2 grams of solute for 100 milliliters of solution

6% NaClO solution → 6 grams of NaClO (solute) for 100 milliliters of solution

Molar mass of NaClO = (22.98 + 35.5 + 16)g/mol = 74.48 g/mol

Atomic mass of Na = 22.98 g/mol

Atomic mass of Cl = 35.5 g/mol

Atomic mass of O = 16 g/mol

1 mol NaClO = 74.48 grams NaClO

74.48 grams NaClO = 1 mol NaClO

6 grams NaClO = (1×6) / 74.48 mole = 0.08055 mole

As unit molarity is mole / liter

So 100 milliliters = 0.1 liters

1 liter = 1000 milliliters

100 milliliters = 100/1000 liters = 0.1 liters

Molarity of NaClO = moles of solute (NaClO) / liters of solution or volume of solution

Molarity of NaClO = 0.08055 / 0.1 mole/L = 0.8055 mole/L

As in question it is mentioned that 'Do not type units into your answer'

So, Molarity of NaClO in clorox bleach = 0.8055

Thus we find out the value of molarity of NaClO in Clorox bleach which came out to be 0.8055 as we dont have to give the answer with units.

Learn more about Molarity here:

brainly.com/question/27208890

#SPJ10

8 0

2 years ago

The photodissociation of ozone by ultraviolet light in the upper atmosphere is a first-order reaction with a rate constant of 1.

atroni [7]

Answer:

[O₃]= 8.84x10⁻⁷M

Explanation:

The photodissociation of ozone by UV light is given by:

O₃ + hν → O₂ + O (1)

The first-order reaction of the equation (1) is:

$rate = k [O_{3}] = - k \frac{\Delta [O_{3}]}{\Delta t}$ (2)

where k: is the rate constant and Δ[O₃]/Δt: is the variation in the ozone concentration with time, and the negative sign is by the decrease in the reactant concentration

We can get the following expression of the first-order integrated law of the reaction (1), by resolving the equation (2):

$[O_{3}]_{t} = [O_{3}]_{0} \cdot e^{-kt}$ (3)

where [O₃](t): is the ozone concentration in the elapsed time and [O₃]₀: is the initial ozone concentration

We can calculate the initial ozone concentration using equation (3):

$[O_{3}]_{t} = 5.0 \cdot 10^{-3}M \cdot e^{-(1.0\cdot 10^{-5}s^{-1}) (\frac{10d \cdot 24h \cdot 3600 s}{1d \cdot 1h})} = 8.84 \cdot 10^{-7}M$

So, the ozone concentration after 10 days is 8.84x10⁻⁷M.

I hope it helps you!

3 0

4 years ago

Why are resources limited

MrRa [10]

Resources can be limited from too much use. Scarcity is one word describing this conundrum. We must be careful with what we use because too much causes harm.

6 0

3 years ago