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Nesterboy [21]
3 years ago
11

1.Compare and contrast the rate of solution formation between the three physical forms of salt that were placed in the vial and

not agitated with the three forms of salt that were placed in the vial and were agitated.
2. On the basis of your results, what is the relationship between the temperature of the solvent and the rate of solution formation?
3. Use your knowledge of collision theory to explain the results of your experiments in this laboratory.
Chemistry
1 answer:
lawyer [7]3 years ago
8 0

<span>The stable form of salt at standard temperature and pressure is solid. If you add water to salt, it will dissolve. However, there are certain factors that affect the rate of solution formation of salt. The rate of formation of salt solution is faster when the vial is agitated than when it is not agitated. By agitating the solution, you are increasing the surface area of the salt particles in contact with water.</span>

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The fact that water requires a large amount of energy before its temperature changes is the result of
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The appropriate answer is d. the high specific heat capacity of water. This unique quality of water makes it suitable as an organic solvent. Specific heat capacity is the energy required to change one gram of a substance by one degree. Organic processes need to be carried out at a specific temperature. The high specific heat capacity of water ensures that environmental changes in temperature.
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Atoms have a blank shape. the blank of an atom is made up of
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<em>Answer:</em>

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How many electrons are in krypton
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Calculate the ph of a solution in which [oh−]=7.1×10−3m.express the ph of the solution to two decimal places.
Phoenix [80]

Answer is: pH value of solution is 11.85.<span>
[</span>OH⁻] = 7.1·10⁻³ M;  equilibrium concentration of hydroxide anions.

[OH⁻]·[H⁺] = Kw.

0.0071 mol/L · [H⁺] = 10⁻¹⁴ mol²/L².

[H⁺] = 10⁻¹⁴ mol²/L² ÷ 7.1·10⁻³ mol/L.

[H⁺] = 1.4·10⁻¹² mol/L.

pH = -log[H⁺].

pH = -log(1.4·10⁻¹² mol/L).

pH = 11.85.

If pH is less than seven, solution is acidic; greater than seven, solution is basic; equal seven, solution is neutral.

6 0
3 years ago
One gram of liquid benzene is burned in a bomb calorimeter. The temperature before ignition was 20.826 C, and the temperature af
Licemer1 [7]

Answer:

fH = - 3,255.7 kJ/mol

Explanation:

Because the bomb calorimeter is adiabatic (q =0), there'is no heat inside or outside it, so the heat flow from the combustion plus the heat flow of the system (bomb, water, and the contents) must be 0.

Qsystem + Qcombustion = 0

Qsystem = heat capacity*ΔT

10000*(25.000 - 20.826) + Qc = 0

Qcombustion = - 41,740 J = - 41.74 kJ

So, the enthaply of formation of benzene (fH) at 298.15 K (25.000 ºC) is the heat of the combustion, divided by the number of moles of it. The molar mass od benzene is: 6x12 g/mol of C + 6x1 g/mol of H = 78 g/mol, and:

n = mass/molar mass = 1/ 78

n = 0.01282 mol

fH = -41.74/0.01282

fH = - 3,255.7 kJ/mol

4 0
4 years ago
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