1.Compare and contrast the rate of solution formation between the three physical forms of salt that were placed in the vial and
not agitated with the three forms of salt that were placed in the vial and were agitated. 2. On the basis of your results, what is the relationship between the temperature of the solvent and the rate of solution formation?
3. Use your knowledge of collision theory to explain the results of your experiments in this laboratory.
<span>The
stable form of salt at standard temperature and pressure is solid. If you add
water to salt, it will dissolve. However, there are certain factors that affect
the rate of solution formation of salt. The rate of formation of salt solution
is faster when the vial is agitated than when it is not agitated. By agitating
the solution, you are increasing the surface area of the salt particles in
contact with water.</span>
Answer is: <span>The reaction will not be spontaneous at any temperature.
</span>
<span>Gibbs free energy
(G) determines if reaction will proceed spontaneously.
ΔG = ΔH - T·ΔS.
ΔG - changes in Gibbs free energy.
ΔH - changes in enthalpy.
ΔS - changes in entropy.
T is temperature in Kelvins.
When ΔS < 0 (negative entropy change) and ΔH > 0
(endothermic reaction), the process is never spontaneous (ΔG> 0).</span>