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Ksju [112]
3 years ago
6

A ball having mass 2 kg is fastened at the end of a flagpole that is connected to the side of a tall building at point P . The l

ength of the flagpole is 4.6 m, and it makes an angle 1.0472 rad (60◦ ) with the horizontal. The acceleration of gravity is 9.8 m/s 2 . If the ball becomes loose and starts to fall, determine the magnitude of its angular momentum after 27 s about P. Neglect air resistance.
Physics
1 answer:
victus00 [196]3 years ago
7 0

Answer:

1217.6 kg m^{2} / s

Explanation:

mass (m) =  2 kg

length (L) = 4.6 m

angle = 1.0472 rad = 60 degrees

acceleration due to gravity (g) = 9.8 m/s^{2}

time (t) = 27 s

angular momentum = m x g x L x t x cosθ

angular momentum = 2 x 9.8 x 4.6 x 27 x cos 60 = 1217.6 kg m^{2} / s

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From laws of motion:

S = ( \frac{v + u}{2} ) \times t
Where S is the distance/displacement (as you would call it) which is unknown
v = final velocity which is 0m/s (this is because the car stops)
u = initial velocity which is 36m/s (from the data given)
t = time taken for the distance to be covered and it is 6s


Substitute the values, hence:
S = ( \frac{0 + 36}{2} ) \times 6
S = (18) \times 6 \\  \\ S = 108m

But this is merely the distance he travelled in the 6 seconds he was trying to stop the car.

Therefore, the distance between the car and the cows = 160-108
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4 years ago
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Answer:

a=5

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3 years ago
George walks to a friend's house. He walks 750 meters North, then realizes he walked too far. He
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76 meters per second
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If a spring stores 5 j of energy when its compressed by 0.5 m. what is the spring constant
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The elastic potential energy stored in a spring is given by:

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