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3 years ago

What’s 1 + 1 many half a window

Physics

2 answers:

Svetach [21]3 years ago

4 0

Answer:

Explanation:

because if you add one to a one it would end up being 2 <3

DENIUS [597]3 years ago

3 0

Answer: 2

Explanation: 1+1=2

This was THE hardest question I've ever decided to answer

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1.Why does the water vapour in clouds condense?

disa [49]

It condenses because the atmosphere above us is much colder than what we feel. We see clouds because clouds aren't entirely water vapor, the water inside of clouds is beginning to change from a gas to a liquid.

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4 years ago

Kinematic: An object drop 20m from a cliff. If it started at rest and is going 20m/s just before it hits the ground, what is it’

Naily [24]

h=average v * time average v = (0+ 20)/2 =10 so: h = 20 = 10 * t --> t = 2 sec final v = v0 + at v0=0 --> 20 = 0 + a*2 -> a = 10 m/s2

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3 years ago

Read 2 more answers

If mass if a manis60kg.calculate his weight on earth and moon if the values of gram are 9.8 meter/second square and 1.6 meter/s

katen-ka-za [31]

Answer:

Explanation:

w = mg, and no matter where we go, our masses will never change. Our weight does, however, depending upon the gravity of where we are. Let's first find the weight of the man on earth, where the pull of gravity is -9.8 m/s/s:

w = (60)(-9.8) so

w = 590 N rounded from 588. It's negative because weight is a downward value (whereas Normal force is the upward value of this measurement, making Normal force the positive of this same number)

Now for the moon, where gravity is 1.6 m/s/s:

w = (60)(-1.6) so

w = -96 N

6 0

3 years ago

Two 10-cm-diameter metal plates 1.0 cm apart are charged to {12.5 nC. They are suddenly connected together by a 0.224-mm- diamet

Alekssandra [29.7K]

Answer:

(a).The maximum current in the wire is $4.217\times10^{5}\ A$ .

(b). The electric field in the wire is $11.2\times10^{5}\ N/C$ .

(c).The current also decrease with time.

(d). The total amount of energy dissipated in the wire is $1.126\times10^{-5}\ J$

Explanation:

Given that,

Diameter of metal plates = 10 cm

Distance between the plates = 1.0 cm

Charged = 12.5 nC

Diameter of copper wire = 0.224 mm

We need to calculate the cross section area of the plates

Using formula of area

$A=\pi r^2$

Put the value into the formula

$A=\pi\times(5\times10^{-2})^2$

$A=7.85\times10^{-3}\ m^2$

We need to calculate the capacitor

Using formula of capacitor

$C=\dfrac{\epsilon_{0}A}{d}$

Put the value into the formula

$C=\dfrac{8.85\times10^{-12}\times7.85\times10^{-3}}{1.0\times10^{-2}}$

$C=6.94\times10^{-12}\ F$

We need to calculate the resistance of the wire

Using formula of resistivity

$R=\dfrac{\rho l}{A}$

Put the value into the formula

$R=\dfrac{1.7\times10^{-8}\times1.0\times10^{-2}}{\pi\times(0.1125\times10^{-3})^2}$

$R=4.27\times10^{-3}\ \Omega$

We need to calculate the voltage

Using formula of charge

$q=CV$

$V=\dfrac{q}{C}$

Put the value into the formula

$V=\dfrac{12.5\times10^{-9}}{6.94\times10^{-12}}$

$V=1.801\times10^{3}\ V$

(a). We need to calculate the current

Using formula of current

$I=\dfrac{V}{R}$

$I=\dfrac{1.801\times10^{3}}{4.27\times10^{-3}}$

$I=421779.85\ A$

$I=4.217\times10^{5}\ A$

(b). We need to calculate the electric field

Using formula of electric field

$E=\dfrac{kq}{r^2}$

Put the value into the formula

$E=\dfrac{9\times10^{9}\times12.5\times10^{-9}}{(1.0\times10^{-2})^2}$

$E=11.2\times10^{5}\ N/C$

The electric field in the wire is $11.2\times10^{5}\ N/C$ .

(c). In this case, the voltage between the capacitor plates decreases as the charge decreases with time.

The current is directly proportional to the voltage between the plates .

Hence, The current also decrease with time.

(d). We need to calculate the total amount of energy dissipated in the wire

Using formula of energy

$E=\dfrac{1}{2}CV^2$

Put the value into the formula

$E=\dfrac{1}{2}\times6.94\times10^{-12}\times(1.801\times10^{3})^2$

$E=1.126\times10^{-5}\ J$

The total amount of energy dissipated in the wire is $1.126\times10^{-5}\ J$

Hence, (a).The maximum current in the wire is $4.217\times10^{5}\ A$ .

(b). The electric field in the wire is $11.2\times10^{5}\ N/C$ .

(c).The current also decrease with time.

(d). The total amount of energy dissipated in the wire is $1.126\times10^{-5}\ J$

8 0

3 years ago

If you are designing a force multiplying system with two pneumatic cylinders. Your system should increase the force by a multipl

Tomtit [17]

Answer:

decrease the area in the second cylinder

Explanation:

In a two-cylinders pneumatic system, the pressure exerted on the first cylinder is equal to the pressure on the second cylinder:

$p_1 = p_2$

We can rewrite the pressure as product between force (F) and area (A) of the cylinder:

$F_1 A_1 = F_2 A_2$

In this system, the output force should be 4 times the input force:

$F_2 = 4 F_1$

Substituting into the previous equation, we get:

$F_1 A_1 = 4 F_1 A_2\\A_2 = \frac{A_1}{4}$

This means that the area of the second cylinder must be 1/4 of the area of the first cylinder, so the correct answer is

decrease the area in the second cylinder

8 0

3 years ago