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inn [45]
3 years ago
9

A circuit is built based on this circuit diagram. What is the equivalent resistance of the circuit?

Physics
2 answers:
Lana71 [14]3 years ago
8 0
All of the resistances are parallel so the total resistance is:
1/Rt = 1/9 + 1/6 + 1/3 the final answer’s 1.636 (B)
zalisa [80]3 years ago
6 0

Answer:

Equivalent resistance of this circuit is 1.6 ohms.

Explanation:

In the given figure, the three resistors are connected in parallel with 12 Volt battery. In parallel combination of resistors, the potential difference across each resistor is same but the current across each resistors divides.

The equivalent resistance is given by :

\dfrac{1}{R_p}=\dfrac{1}{R_1}+\dfrac{1}{R_2}+\dfrac{1}{R_3}

Here, R₁ = 3 ohms, R₂ = 6 ohms and R₃ = 9 ohms

\dfrac{1}{R_p}=\dfrac{1}{3}+\dfrac{1}{6}+\dfrac{1}{9}

R_p=1.6\ \Omega

Hence, the equivalent resistance of this circuit is 1.6 ohms.

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a) θ₁ = 23.14 ° , b) θ₂ = 51.81 °

Explanation:

An address network is described by the expression

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Second order

     θ₂ = sin⁻¹ (2 6.5628 10⁻⁷ / 1.67 10⁻⁶)

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     θ₂ = 51.81 °

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