Answer:
There is 0.466 KW required to operate this air-conditioning system
Explanation:
<u>Step 1:</u> Data given
Heat transfer rate of the house = Ql = 755 kJ/min
House temperature = Th = 24°C = 24 +273 = 297 Kelvin
Outdoor temperature = To = 35 °C = 35 + 273 = 308 Kelvin
<u>Step 2: </u> Calculate the coefficient of performance o reversed carnot air-conditioner working between the specified temperature limits.
COPr,c = 1 / ((To/Th) - 1)
COPr,c = 1 /(( 308/297) - 1)
COPr,c = 1/ 0.037
COPr,c = 27
<u>Step 3:</u> The power input cna be given as followed:
Wnet,in = Ql / COPr,max
Wnet, in = 755 / 27
Wnet,in = 27.963 kJ/min
Win = 27.963 * 1 KW/60kJ/min = 0.466 KW
There is 0.466 KW required to operate this air-conditioning system
Answer:Counter,
0.799,
1.921
Explanation:
Given data
Since outlet temperature of cold liquid is greater than hot fluid outlet temperature therefore it is counter flow heat exchanger
Equating Heat exchange
=
we can see that heat capacity of hot fluid is minimum
Also from energy balance
=
NTU=1.921
OSHA inspections are generally unannounced. In fact, except in four exceptional circumstances when advance notice may be given.
It is a criminal offense for any person to give unauthorized advance notice of an OSHA inspection.
Its safe because it isn't something with electricity
Answer:
I do!!
Explanation:
I have to sit for 3 hours lol♀️