Answer:
Heat flux of CO₂ in cgs
= 170.86 x 10⁻⁹ mol / cm²s
SI units
170.86 x 10⁻⁸ kmol/m²s
Explanation:
Answer:
note:
solution is attached due to error in mathematical equation. please find the attachment
Answer:
ddddddddddddddddddddddddddddd
Explanation:
cccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccc
Answer:
![D=0.41m](https://tex.z-dn.net/?f=D%3D0.41m)
Explanation:
From the question we are told that:
Discharge rate ![V_r=0.35 m3/s](https://tex.z-dn.net/?f=V_r%3D0.35%20m3%2Fs)
Distance ![d=4km](https://tex.z-dn.net/?f=d%3D4km)
Elevation of the pumping station ![h_p= 140 m](https://tex.z-dn.net/?f=h_p%3D%20140%20m)
Elevation of the Exit point ![h_e= 150 m](https://tex.z-dn.net/?f=h_e%3D%20150%20m)
Generally the Steady Flow Energy Equation SFEE is mathematically given by
![h_p=h_e+h](https://tex.z-dn.net/?f=h_p%3Dh_e%2Bh)
With
![P_1-P_2](https://tex.z-dn.net/?f=P_1-P_2)
And
![V_1=V-2](https://tex.z-dn.net/?f=V_1%3DV-2)
Therefore
![h=140-150](https://tex.z-dn.net/?f=h%3D140-150)
![h=10](https://tex.z-dn.net/?f=h%3D10)
Generally h is give as
![h=\frac{0.5LV^2}{2gD}](https://tex.z-dn.net/?f=h%3D%5Cfrac%7B0.5LV%5E2%7D%7B2gD%7D)
![h=\frac{8Q^2fL}{\pi^2 gD^5}](https://tex.z-dn.net/?f=h%3D%5Cfrac%7B8Q%5E2fL%7D%7B%5Cpi%5E2%20gD%5E5%7D)
Therefore
![10=\frac{8Q^2fL}{\pi^2 gD^5}](https://tex.z-dn.net/?f=10%3D%5Cfrac%7B8Q%5E2fL%7D%7B%5Cpi%5E2%20gD%5E5%7D)
![D=^5\frac{8*(0.35)^2*0.003*4000}{3.142^2*9.81*10}](https://tex.z-dn.net/?f=D%3D%5E5%5Cfrac%7B8%2A%280.35%29%5E2%2A0.003%2A4000%7D%7B3.142%5E2%2A9.81%2A10%7D)
![D=0.41m](https://tex.z-dn.net/?f=D%3D0.41m)