All categories

2 years ago

In a slowly cooled hypereutectoid iron-carbon steel, the pearlite colonies are

1 answer:

7 0

In a slowly cooled hypereutectoid iron-carbon steel, the pearlite colonies are normally separated from each other by a more or less continuous boundary layer of cementite done by Slower cooling reasons coarse Pearlite, even as rapid cooling reasons first-rate pearlite to form.

<h3>What levels is in Hypereutectoid metal?</h3>

Hypoeutectoid steels can, upon preliminary cooling from the austenite single segment field, exist as extraordinary levels, eutectoid ferrite and austenite, every with extraordinary carbon contents.

At room temperature, hypereutectoid steels have a pearlitic primary microstructure (ferrite grains with embedded cementite lamellae) with moreover induced cementite on the grain boundaries! The micrograph under suggests a hypereutectoid metal with 1.0 Carbon (C100).

You might be interested in

In an oscillating LC circuit, L ! 25.0 mH and C ! 7.80 mF. At time t 0 the current is 9.20 mA, the charge on the capacitor is 3.

topjm [15]

Answer:

a) 926 μJ

b) 3.802 mC

c) 8.61 A

d) 0.0721

e) 3.2137

Explanation:

The energy in the inductor is

$El = \frac{1}{2}*L*I^2$

$El = \frac{1}{2}*25*10^{-3}*(9.2*10^{-3})^2 = 1.06*10^{-6} J = 1.06 \mu J$

The energy store in a capacitor is

$Ec = \frac{1}{2}*C*V^2$

The voltage in a capacitor is

V = Q/C

$V = \frac{3.8*10^{-3}}{7.8*10^{-3}} = 0.487 V$

Therefore:

$Ec = \frac{1}{2}*7.8*10^{-3}*0.487^2 = 9.256*10^{-4} J = 925.6 \mu J$

The total energy is Et = 925.6 + 1.1 = 926.7 μJ

At a certain point all the energy of the circuit will be in the capacitor, at this point it will have maximum charge

$Ec = \frac{1}{2}*C*V^2$

V = Q/C

$Ec = \frac{1}{2}*C*(\frac{Q}{C})^2$

$Ec = \frac{1}{2}*\frac{Q^2}{C}$

$Q^2 = 2*Ec*C$

$Q = \sqrt{2*Ec*C}$

$Q = \sqrt{2*926*10{-6}*7.8*10^{-3}} = 3.802 * 10{-3} C = 3.802 mC$

When the capacitor is completely empty all the energy will be in the inductor and current will be maximum

$El = \frac{1}{2}*L*I^2$

$I^2 = 2*\frac{El}{L}$

$I = \sqrt{2*\frac{El}{L}}$

$I = \sqrt{2*\frac{926.7*10^{-3}}{25*10^{-3}}} = 8.61 A$

At t = 0 the capacitor has a charge of 3.8 mC, the maximum charge is 3.81 mC

q = Q * cos(vt + f)

q(0) = Q * cos(v*0 + f)

3.8 = 3.81 * cos(f)

cos(f) = 3.8/3.81

f = arccos(3.8/3.81) = 0.0721

If the capacitor is discharging it is a half cycle away, so f' = f + π = 3.2137

4 0

3 years ago

What Happens If A Sonic Boom Is Created?

Volgvan

Answer:

Explanation:

A sonic boom is a loud sound kind of like an explosion. It's caused by shock waves created by any object that travels through the air faster than the speed of sound. Sonic booms create huge amounts of sound energy. When an object moves through the air, it makes pressure waves in front of and behind it.

8 0

3 years ago

Which of the following explains the purpose of a convertible screwdriver?

aliya0001 [1]

Answer:

The correct option is;

To be able to switch between different heads quickly and easily

Explanation:

A screwdriver is a tool or device that has a grip handle which surrounds an extension shaft that has a forged tip that fits into the complementary groove on a screw head such that by turning the handle while the forged head of the screwdriver sits in a screw head, the screw is turned

A convertible screw driver is built with the capability to easily change the tip or other attributes of the screwdriver quickly.

7 0

3 years ago

2.2 k omega= _____ omega

neonofarm [45]

Explanation:

2.2 k omega= ___2200__ omega

here k is kilo so simply multiply by 1000

8 0

3 years ago

Brittle failure is a type of failure in which: (a) There is large amount of plastic deformation (b) Large amount of elastic defo

sp2606 [1]

Answer:

c). Very little plastic and elastic deformation

Explanation:

Brittle failure is a sudden, very rapid crack where there is no sign of any plastic deformation or ductility. The failure is not stable unlike ductile failure and the the crack propagates very fast without any further increase of any stress. In brittle failure there is very little plastic deformation and low energy is absorbed before fracture takes place.

Thus, very little plastic and elastic deformation takes place in brittle failure.

7 0

3 years ago