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Sholpan [36]
2 years ago
14

In a slowly cooled hypereutectoid iron-carbon steel, the pearlite colonies are

Engineering
1 answer:
jek_recluse [69]2 years ago
7 0

In a slowly cooled hypereutectoid iron-carbon steel, the pearlite colonies are normally separated from each other by a more or less continuous boundary layer of cementite done by Slower cooling reasons coarse Pearlite, even as rapid cooling reasons first-rate pearlite to form.

<h3>What levels is in Hypereutectoid metal?</h3>

Hypoeutectoid steels can, upon preliminary cooling from the austenite single segment field, exist as extraordinary levels, eutectoid ferrite and austenite, every with extraordinary carbon contents.

At room temperature, hypereutectoid steels have a pearlitic primary microstructure (ferrite grains with embedded cementite lamellae) with moreover induced cementite on the grain boundaries! The micrograph under suggests a hypereutectoid metal with 1.0 Carbon (C100).

Read more about the cementite:

brainly.com/question/24924853

#SPJ1

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If the old radiator is replaced with a new one that has longer tubes made of the same material and same thickness as those in th
Nookie1986 [14]

Answer: hello some parts of your question is missing attached below is the missing information

The radiator of a car is a type of heat exchanger. Hot fluid coming from the car engine, called the coolant, flows through aluminum radiator tubes of thickness d that release heat to the outside air by conduction. The average temperature gradient between the coolant and the outside air is about 130 K/mm . The term ΔT/d  is called the temperature gradient which is the temperature difference ΔT between coolant inside and the air outside per unit thickness of tube

answer : Total surface area = 3/2 * area of old radiator

Explanation:

we will use this relation

K = \frac{Qd }{A* change in T }

change in T =  ΔT  

therefore New Area  ( A ) = 3/2 * area of old radiator

Given that the thermal conductivity is the same in the new and old radiators

3 0
3 years ago
Suppose the working pressure for a boiler is 10 psig, then what is the corresponding absolute pressure?
yanalaym [24]

Answer:

The corresponding absolute pressure of the boiler is 24.696 pounds per square inch.

Explanation:

From Fluid Mechanics, we remember that absolute pressure (p_{abs}), measured in pounds per square inch, is the sum of the atmospheric pressure and the working pressure (gauge pressure). That is:

p_{abs} = p_{atm}+p_{g} (1)

Where:

p_{atm} - Atmospheric pressure, measured in pounds per square inch.

p_{g} - Working pressured of the boiler (gauge pressure), measured in pounds per square inch.

If we suppose that p_{atm} = 14.696\,psi and p_{g} = 10\,psi, then the absolute pressure is:

p_{abs} = 14.696\,psi+10\,psi

p_{abs} = 24.696\,psi

The corresponding absolute pressure of the boiler is 24.696 pounds per square inch.

8 0
3 years ago
Xyxyydfufggivivihogcufuf​
Genrish500 [490]

Answer:

ummm why is you doing this

Explanation:

It doesnt make sense.

7 0
4 years ago
Why does the ring on saturn spin
spayn [35]

Answer: THERE IS NO GRAVITY IN SPACE SO ROCKS SPIN

Explanation:

8 0
3 years ago
Read 2 more answers
What is a combination circuit? A combination circuit:
Anon25 [30]

Answer:

Combination circuit; The basic strategy for the analysis of combination circuits involves using the meaning of equivalent resistance for parallel branches to transform the combination circuit into a series circuit.

Example:

The use of both series and parallel connections within the same circuit. In this case, light bulbs A and B are connected by parallel connections and light bulbs C and D are connected by series connections. This is an example of a combination circuit.

7 0
3 years ago
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