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2 years ago

In a slowly cooled hypereutectoid iron-carbon steel, the pearlite colonies are

1 answer:

7 0

In a slowly cooled hypereutectoid iron-carbon steel, the pearlite colonies are normally separated from each other by a more or less continuous boundary layer of cementite done by Slower cooling reasons coarse Pearlite, even as rapid cooling reasons first-rate pearlite to form.

<h3>What levels is in Hypereutectoid metal?</h3>

Hypoeutectoid steels can, upon preliminary cooling from the austenite single segment field, exist as extraordinary levels, eutectoid ferrite and austenite, every with extraordinary carbon contents.

At room temperature, hypereutectoid steels have a pearlitic primary microstructure (ferrite grains with embedded cementite lamellae) with moreover induced cementite on the grain boundaries! The micrograph under suggests a hypereutectoid metal with 1.0 Carbon (C100).

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What is the difference between a cost and a benefit?

goblinko [34]

Answer:

A cost is something you have to give up or sacrifice and a benefit is something that is gained or is helpful.

Explanation:

In a cost-benefit analysis of a system, an engineer is to simply look at the requirements for the system and determine the costs to build the system, both in financial value and energy value. Additionally, the engineer needs to determine the benefits that would come from choosing a particular path of cost. If the benefits outweigh the cost for the project, then the solution is accepted. Else, the cost outweighs the benefit and the solution is rejected.

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3 years ago

In 2008 502 motorcyclists fire in Florida - an increase from The number killed in 2004

faltersainse [42]

Is this a question ?

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4 years ago

A spur gearset has a module of 6 mm and a velocity ratio of 4. The pinion has 16 teeth. Find the number of teeth on the driven g

levacccp [35]

Answer:

NG=64 teeth

dG=384mm

dP=96mm

C=240mm

Explanation:

step one:

given data

module m=6mm

velocity ratio VR=4

number of teeth of pinion Np=16

Step two:

Required

1. Number of teeth on the driven gear

$N_G=N_P*V_R\\\\N_G=16*4\\\\N_G=64$

The driven gear has 64 teeth

2. The pitch diameters

The driven gear diameter

$d_G=N_G*m\\\\d_G=64*6\\\\d_G=384$

The driven gear diameter is 384mm

The pinion diameter

$d_P=N_P*m\\\\d_P=16*6\\\\d_P=96$

Pinion diameter is 96mm

3. Theoretical center-to-center distance

$C=\frac{d_G+d_P}{2} \\\\C=\frac{384+96}{2} \\\\C=\frac{480}{2}\\\\C=240$

The theoretical center-to-center distance is 240mm

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3 years ago

Describe the cycle that purifies drinking water. 40 points

Sunny_sXe [5.5K]

Umm the Water cycle sorry I’m trying

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4 years ago

Read 2 more answers

2. A thin vertical panel L = 3 m high and w = 1.5 m wide is thermally insulated on one side and exposed to a solar radiation flu

n200080 [17]

Answer: 383.22K

Explanation:

L = 3m, w = 1.5m

Area A = 3 x 1.5 = 4.5m2

Q' = 750W/m2 (heat from sun) ,

& = 0.87

Q = &Q' = 0. 87x750 = 652.5W/m2

E = QA = 652.5 x 4.5 = 2936.25W

T(sur) = 300K, T(panel) = ?

Using E = §€A(T^4(panel) - T^4(sur))

§ = Stefan constant = 5.7x10^-8

€ = emmisivity = 0.85

2936.25 = 5.7x10^-8 x 0.85 x 4.5 x (T^4(panel) - 300^4)

T(panel) = 383.22K

See image for further details.

5 0

3 years ago