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Oksana_A [137]
3 years ago
14

A student sets up two reactions. reaction 1 uses 0.130 mol/l of reactant, and reaction 2 uses 0.440 mol/l of reactant. how many

times faster is reaction 2 compared to reaction 1?

Chemistry
2 answers:
erastova [34]3 years ago
7 0

Reaction 2 is 3.385 times faster compared to reaction 1

<h3>Further explanation</h3>

The reaction rate (v) shows the change in the concentration of the substance (changes in addition to concentrations for reaction products or changes in concentration reduction for reactants) per unit time.

Can be formulated:

Reaction: aA ---> bB

\large{\boxed{\boxed{\bold{v~=~-\frac{\Delta A}{\Delta t}}}}

or

\large{\boxed{\boxed{\bold{v~=~+\frac{\Delta B}{\Delta t}}}}

A = reagent

B = product

v = reaction rate

t = reaction time

For A + B reactions ---> C + D

Reaction speed can be formulated:

\large{\boxed{\boxed{\bold{v~=~k.[A]^a[B]^b}}}

where

v = reaction speed, M / s

k = constant, mol¹⁻⁽ᵃ⁺ᵇ⁾. L⁽ᵃ⁺ᵇ⁾⁻¹. S⁻¹

a = reaction order to A

b = reaction order to B

[A] = [B] = concentration of substances

Reaction 1 uses 0.130 mol / l of reactant, and reaction 2 uses 0.440 mol / l of reactant.

Assuming a reaction order is one then:

reaction rate 1 =

v₁ = k. [A]

v₁ = k. 0.130

reaction rate 2 =

v₂ = k. [B]

v₂ = k. 0.440, so that

\frac{v_2}{v_1}~=~k.\frac{0.440}{0.130}

\frac{v_2}{v_1}~=~3,385

v₂ = 3.385. v₁

<h3>Learn more</h3>

the factor can decrease the rate of a chemical reaction

brainly.com/question/807610

increase the rate of a chemical reaction

brainly.com/question/1569924

Which of the following does not influence the effectiveness of a detergent

brainly.com/question/10136601

Keywords: reaction rate, reaction order, molar concentration, products, reactants

Furkat [3]3 years ago
5 0

<u>Given:</u>

Concentration of reactant used in reaction 1 = 0.130 mol/L

Concentration of reactant used in reaction 2 = 0.440 mol/L

<u>To determine:</u>

the rate of reaction 2 wrt to 1

<u>Explanation:</u>

Let the reaction be represented as:

Reactant → Product

Rate of reaction is:

[Rate] = k[reactant]

where k = rate constant

[reactant] = reactant concentration

for reactions 1 and 2 the rates are given as:

[Rate]₁ = k[reactant]₁=k[0.130] -------(1)

[Rate]₂= k[reactant]₂=k[0.440]--------(2)

2 ÷ 1

[Rate]₂/[Rate]₁ = 3.38

[Rate]₂ = 3.38[Rate]₁

Ans: Thus, reaction(2) is nearly 3 times faster than reaction(1)

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