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Ivan
3 years ago
13

Ty’s experimental probability of winning a certain game is 1/3. Jana’s expiremental probability of winning the same game is 3/4.

If Ty and Jana each played the game 120 times, how many more games would Jana expect to win over Ty?
Mathematics
1 answer:
Dafna1 [17]3 years ago
4 0

Answer:

Jana is expected to win 40 more games over Ty.

Step-by-step explanation:

If Ty plays the game 120 times, he is expected to win in 1/3 part of 120 games, which is ( 1/3 * 120 =) 40 games.

If Jana plays the game 120 times, she is expected to win in 2/3 part of 120 games, which is ( 2/3 * 120 =) 80 games.

If Jana is expected to win 80 times an Ty is expected to 40 times, then Jana is expected to win ( 80 - 40 =) 40 more games over Ty.

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Answer:

x = 15

Step-by-step explanation:

Substitute: -4/5x + 7 = -5

Rearrange unknown terms to the left side of the equation: -4/5x = -5 - 7

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2 years ago
Find m∠U.<br> Write your answer as an integer or as a decimal rounded to the nearest tenth.
olga2289 [7]

Answer:

Answer:

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