How many moles of pbr3 contain 3.68 × 1025 bromine atoms?

1 answer:

6 0

The number of Pbr3 that contain 3.68 x10^ 25 bromine atoms is 60.631 moles

calculation

by use of Avogadro law constant
that is, 1 moles = 6.02 x10^23 atoms

what about 3.65 x10^25 atoms

by cross multiplication

= (1 mole x 3.65 x 10 ^25 atoms) / ( 6.02 x10^23 atoms) = 60.631 moles
atoms and atoms cancel out each other

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