How many moles of pbr3 contain 3.68 × 1025 bromine atoms?
1 answer:
The number of Pbr3 that contain 3.68 x10^ 25 bromine atoms is 60.631 moles
calculation
by use of Avogadro law constant
that is, 1 moles = 6.02 x10^23 atoms
what about 3.65 x10^25 atoms
by cross multiplication
= (1 mole x 3.65 x 10 ^25 atoms) / ( 6.02 x10^23 atoms) = 60.631 moles
atoms and atoms cancel out each other
You might be interested in
Fresh water freezes faster
Answer:
6,8 g
Explanation:
c = 4.18 J/(g * °C) = 4180 J / (kg * °C)
= 25 °C
= 36,4 °C
Q = 325 J
The formula is: Q = c * m * (
)
m =
Calculating:
m = 325 / 4180 * (36,4 - 25) ≈ 0,0068 kg = 6,8 g
Answer:
<h3>A-5N B-6N C-7N D-8N</h3>
Explanation:
i hope it helps ;)
Answer: 40.38 L
Explanation:
Formula: P1V1 = P2V2
(1.55)(52.1) = (2.00)(x)
80.755 = 2x
40.38 = x
2) Should be tested by the scientific community