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Liono4ka [1.6K]
3 years ago
14

How many moles of pbr3 contain 3.68 × 1025 bromine atoms?

Chemistry
1 answer:
Tcecarenko [31]3 years ago
6 0
The number  of Pbr3  that   contain   3.68  x10^ 25  bromine  atoms is  60.631  moles


      calculation

by  use of Avogadro  law constant 
that is,   1  moles =  6.02  x10^23   atoms

what   about  3.65  x10^25  atoms

by   cross  multiplication

= (1 mole  x 3.65 x  10 ^25  atoms)  /  ( 6.02  x10^23  atoms)  = 60.631  moles
atoms and  atoms  cancel  out  each  other
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Help please with question number 16)
Zanzabum

Answer:

Mg²⁵   =   10.00%    

Mg²⁶   =   45.04%

Mg²⁴   =   44.96%

Explanation:

Given data:

Atomic mass of Mg²⁶ = 25.983

Atomic mass of Mg²⁵ = 24.986

Atomic mass of Mg²⁴ = 23.985

Abundance of Mg²⁵ = 10.00%

Abundance of Mg²⁶ = ?

Abundance of Mg²⁴ = ?

Solution:

Average atomic weight of Mg = 25.983  + 24.986+ 23.985 / 3

Average atomic weight of Mg = 74.954/3

Average atomic weight of Mg = 24.985 amu

Abundance of          

Mg²⁵   =   10.00    

Mg²⁶   =    x      

Mg²⁴   =   100- 10 - x = 90 -x    

Formula:

Average atomic mass  = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) + (abundance of 3rd isotope × its atomic mass)  / 100

24.985 = (0.1×24.986)+(90-x×23.985) + ( x ×25.983 )  /100

24.985 =  249.86 + 2158.65 - 23.985x + 25.983x  / 100

24.985 = 2408.51 + 1.998 x / 100

2498.5 = 2408.51 + 1.998 x

1.998 x = 2498.5 - 2408.51

1.998 x = 89.99

x = 89.99 /1.998

x = 45.04

Now we put the value of x:

Mg²⁵   =   10.00    

Mg²⁶   =    x  (45.04)

Mg²⁴   =   90 -x   (90 - 45.04 = 44.96)

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