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Illusion [34]
3 years ago
10

What is the half-life of sodium-25 if 1.00 gram of a 16.00-gram sample of sodium-25 remains unchanged after 237 seconds?

Chemistry
1 answer:
Readme [11.4K]3 years ago
8 0
Given,
1 gram remain out of 16 grams after 237 seconds.

So, 
1g -> 2g -> 4g -> 8g -> 16g
So, 4 half lives have taken palce.

So,
we divide 237 by 4 and we get our answer.

So,
234 / 4 = 59.25 ≈ 59.3

So, the answer is (2) 59.3 seconds
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List three ways the rate of solvation of sodium chloride in water may be<br> increased
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Answer:

1) Increasing temperature

2) Stirring

3) Increasing surface area  of salt by grinding it

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3 years ago
Electrical energy is used to turn the blades of a fan. The amount of energy transformed is seen here: 750 J electrical energy is
Alchen [17]

B) It was transformed into 350 J of heat energy.

Explanation:

The remaining 350J of energy must have been transformed into 350J of heat energy.

A fan works by converting electrical energy into heat energy.

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learn more:

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6 0
4 years ago
How do the electrons in bonds (bonding domains) differ from lone pairs (non-bonding domains)?
max2010maxim [7]

The electrons in bonds (bonding domains) differ from lone pairs (non-bonding domains) is because the bonding domains are bonded to the central atom vs the lone pairs are just stuck on as extra electrons. The difference of bonding domains from non-bonding domains is that the bonding domains are bonded to the central atom and the non-bonding domains are just stuck on as extra electrons.

5 0
3 years ago
The combustion of acetylene gas is represented by this equation: 2C2H2(g) + 5O2(g) → 4CO2(g) + 2H2O(g)
MAVERICK [17]

Answer:

Approximately 2.46\; \rm mol.

Explanation:

Make use of the molar mass data (M({\rm C_2H_2}) = 26.04\; \rm g \cdot mol^{-1}) to calculate the number of moles of molecules in that 64.0\; \rm g of \rm C_2H_2:

\begin{aligned}n({\rm C_2H_2}) &= \frac{m({\rm C_2H_2})}{M} \\ &= \frac{64.0\; \rm g}{26.04\; \rm g\cdot mol^{-1}}\approx 2.46\; \rm mol\end{aligned}.

Make sure that the equation for this reaction is balanced.

Coefficient of \rm C_2H_2 in this equation: 2.

Coefficient of \rm H_2O in this equation: 2.

In other words, for every two moles of \rm C_2H_2 that this reaction consumes, two moles of \rm H_2O would be produced.

Equivalently, for every mole of \rm C_2H_2 that this reaction consumes, one mole of \rm H_2O would be produced.

Hence the ratio: \displaystyle \frac{n({\rm H_2O})}{n({\rm C_2H_2})} = \frac{2}{2} = 1.

Apply this ratio to find the number of moles of \rm H_2O that this reaction would have produced:

\begin{aligned}n({\rm H_2O}) &= n({\rm C_2H_2}) \cdot \frac{n({\rm H_2O})}{n({\rm C_2H_2})} \\ &\approx 2.46\; \rm mol \times 1 = 2.46\; \rm mol\end{aligned}.

3 0
3 years ago
How do crickets make sound from your their leg right?
Reptile [31]
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5 0
3 years ago
Read 2 more answers
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