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2 years ago

7. At what structures in the lungs do the exchange of oxygen and carbon dioxide take place?

2 answers:

8 0

It occurs in the lungs between the alveoli and a network of tiny blood vessels called capillaries, which are located in the walls of the alveoli. The walls of the alveoli actually share a membrane with the capillaries in which oxygen and carbon dioxide move freely between the respiratory system and the bloodstream.

mrs_skeptik [129]2 years ago

3 0

Answer:

Answer is Alveoli

Hope it helps.... plz mark as brainliest

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In this reaction, what roll does the lead (II) nitrate play when 50.0 mL of 0.100M iron (III) chloride are mixed with 50.0 mL of

scoundrel [369]

Lead(II) nitrate will react with iron(III) chloride to produce the precipitate lead(II) chloride as shown in the balanced reaction
2FeCl3(aq) + 3Pb(NO3)2(aq) → 2Fe(NO3)3(aq) + 3PbCl2(s)
Calculating the amount of the precipitate lead(II) chloride each reactant will produce:
mol PbCl2 = 0.050L Pb(NO3)2 (0.100mol/1L)(3mol PbCl2/3mol Pb(NO3)2)
= 0.00500mol PbCl2
mol PbCl2 = 0.050L FeCl3 (0.100mol FeCl3/1L)(3mol PbCl2/2mol FeCl3) = 0.00750mol PbCl2
The reactant Pb(NO3)2 produces a lesser amount of the precipitate PbCl2, therefore, the lead(II) nitrate is the limiting reagent for this reaction.

8 0

2 years ago

Read 2 more answers

The mass of a 50-mL volumetric flask is 40.638 g. After adding 15.0 mL of 95% ethanol and adding enough water to complete the vo

Nuetrik [128]

Answer

0.9516 grams / mL (50.00 has 4 sig digs.)

Remark

You have a couple of extraneous numbers there. You don't care about anything except the mass of the flask + water/alcohol mixture (88.219 grams). and the mass of the flask (40.638 grams)

Formulas

mass water/alcohol mixture = mass of the flask with fluid - mass flask
density = mass / volume

Solution

mass water/alcohol mixture = 88.219 - 40.638 = 47.581

Volume = 50 mL
Density = mass / Volume
Density = 47.581/50
Density = 0.95162 There are 4 sig digs so the answer should be
0.9516

3 0

3 years ago

How many moles of calcium chloride would react with 5. 99 moles of aluminum oxide?

slega [8]

There are 17.97 moles of calcium chloride would react with 5. 99 moles of aluminum oxide .

The balanced chemical equation between reaction between calcium chloride and aluminum oxide is given as,

$3CaCl_{2} (aq)+Al_{2} O_{3} (s)$ → $3CaO_{2} (s)+2Al Cl_{3} (aq)$

The molar ratio of above reaction is 3:1

It means 3 moles of calcium chloride is require to react one mole of aluminum oxide.

The number of moles of calcium chloride requires to react with 5. 99 moles of aluminum oxide = 3 × 5. 99 = 17.97 moles

The equation in which number of atoms of elements in reactant side is equal to the number of atoms of elements in product side is called balanced chemical equation .

learn more about calcium chloride

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6 0

1 year ago

The activation energy of a reaction is 56.9 kj/mol and the frequency factor is 1.5×1011/s. Part a calculate the rate constant of

Vanyuwa [196]

We will use Arrehenius equation

lnK = lnA -( Ea / RT)

R = gas constant = 8.314 J / mol K

T = temperature = 25 C = 298 K

A = frequency factor

ln A = ln (1.5×10 ^11) = 25.73

Ea = activation energy = 56.9 kj/mol = 56900 J / mol

lnK = 25.73 - (56900 / 8.314 X 298) = 2.76

Taking antilog

K = 15.8

5 0

3 years ago

The _______ elements tend to lose electrons and form positive ions, while the _______ elements tend to gain electrons and form n

Jet001 [13]

Actions form positive ions while anions forms negative

7 0

3 years ago

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