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Phoenix [80]
3 years ago
10

a horse moves a sleigh 1.00 kilometers by applying a horizontal 2000 Newton force on its harness for 45 minutes. what is the pow

er of the horse?
Physics
1 answer:
tatyana61 [14]3 years ago
8 0
--  If 2,000 newtons of force were applied through a distance of 1,000 meters,
then 2,000,000 newton-meters = 2,000,000 joules of work were done.

-- 45 minutes = (45 x 60) = 2,700 seconds

-- Power = (work) / (time) = (2,000,000 j) / (2,700 s) = <u>740.74 watts</u>

Interestingly, that's almost exactly 1 horsepower.  (0.99295... of 746 watts)
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Since the noble gases are stable (VERY unreactive), oxygen would like to look like one in terms of the number and arrangement of
iogann1982 [59]

Answer:

oxygen gains two electron to attain electron configuration like neon. Oe-²

Explanation:

3 0
3 years ago
A metal rod of length 2.0 m is moved at 6.0 m/s in a direction perpendicular to its length. A 5.0 mT magnetic field is perpendic
Lerok [7]

Answer:

<h2>The potential difference is 60mV</h2>

Explanation:

 This problem bothers on  application of the expression for motion emf which is expressed as

E= Blv

where B= magnetic field in Tesla

           l= length of the conductor

           v= speed of conductor

Given data

l= 2 meters

v= 6 m/s

B= 5 Tesla

Applying the formula we have

E=5*2*6= 60mV

7 0
3 years ago
Reading glasses of what power are needed for a person whose near point is 125 cm , so that he can read a computer screen at 54 c
Burka [1]

Answer:

1.11 dioptre

Explanation:

d_{i} = Distance of the image = - (125 - 2) = - 123 cm

d_{o} = Distance of the object = 54 - 2 = 52 cm

f = Focal length of the lens

Using the equation

\frac{1}{d_{o}} + \frac{1}{d_{i}} = \frac{1}{f}

\frac{1}{52} + \frac{- 1}{123} = \frac{1}{f}

f = 90.1 cm

Power of the lens is given as

P = \frac{100}{f}

P = \frac{100}{90.1}

P = 1.11 Dioptre

3 0
3 years ago
The block has a weight of 75 lblb and rests on the floor for which μkμk = 0.4. The motor draws in the cable at a constant rate o
WINSTONCH [101]

The given question is incomplete. The complete question is as follows.

The block has a weight of 75 lb and rests on the floor for which \mu k = 0.4. The motor draws in the cable at a constant rate of 6 ft/sft/s. Neglect the mass of the cable and pulleys.

Determine the output of the motor at the instant \theta = 30^{o}.

Explanation:

We will consider that equilibrium condition in vertical direction is as follows.

           \sum F_{y} = 0

         N - W = 0

           N = W

or,      N = 75 lb

Again, equilibrium condition in the vertical direction is  as follows.

        \sum F_{x} = 0

       T_{2} - F_{k} = 0

         T_{2} = \mu_{k} N

                  = 0.4 \times 75 lb

                  = 30 lb

Now, the equilibrium equation in the horizontal direction is as follows.

         \sum F_{x} = 0

       T Cos (30^{o}) + T Cos (30^{o}) = T_{2}

          2T Cos (30^{o}) = T_{2}

    or,             T = \frac{T_{2}}{2 Cos (30^{o})}

                        = \frac{30}{2 Cos (30^{o})}

                        = \frac{30}{1.732}

                        = 17.32 lb

Now, we will calculate the output power of the motor as follows.

             P = Tv

                = 17.32 lb \times 6

                = 103.92 \times \frac{1}{550} \times \frac{hp}{ft/s}

                = 0.189 hp

or,             = 0.2 hp

Thus, we can conclude that output of the given motor is 0.2 hp.

3 0
3 years ago
Read 2 more answers
Which of these statements would best explain the problem encountered with nuclear waste disposal? A) The isotopes have a long ha
algol13
That's right, the correct answer is
<span>A) The isotopes have a long half-life and only remain radioactive for a long time period

The half life of an isotope is the time it takes for the amount of the sample to reduce to half of its initial value. If an isotope has a long half-life, it means it takes a long time to reduce down to a significant level, so it will remain radioactive for a long time period.</span>
4 0
4 years ago
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