Drag is passive, therefore it does not act on gravity. Drag is a mechanical resistance to motion. If the motion in question was induced by gravity drag it can impede that motion, but has no effect on the gravity.
hope this helps!
When a substance boils the molecules within the substance move faster and farther apart, meaning (depending on the current matter state of the substance) molecules will go into more liquid and gaseous states
solid----> liquid ----> gas
In the case of something boiling the substance goes from liquid to gas due to the increased molecular activity because to heat...
Answer:
3.33, 4.84
Explanation:
A) Actual coefficient of performance can be calculated by the formula stated below
Actual COP = heat delivered/ work required
Actual COP = 2,000/600
Actual COP = 3.33
B) Th = High temperature = 80°C + 273 = 353K
Tl = Low temperature = 7°C + 273 = 280K
The theoretical maximum coefficient of performance can ve calculated by the formula
Theoretical COP = Th/(Th-Tl)
Theoretical COP = 353/(353-280)
Theoretical COP = 353/73
Theoretical COP = 4.84
Answer:
0.71 m/s
Explanation:
We find the time it takes the stone to hit the water.
Using y = ut - 1/2gt² where y = height of bridge, u = initial speed of stone = 0 m/s, g = acceleration due to gravity = -9.8 m/s² (negative since it is directed downwards)and t = time it takes the stone to hit the water surface.
So, substituting the values of the variables into the equation, we have
y = ut - 1/2gt²
82.2 m = (0m/s)t - 1/2( -9.8 m/s²)t²
82.2 m = 0 + (4.9 m/s²)t²
82.2 m = (4.9 m/s²)t²
t² = 82.2 m/4.9 m/s²
t² = 16.78 s²
t = √16.78 s²
t = 4.1 s
This is also the time it takes the raft to move from 5.04 m before the bridge to 2.13 m before the bridge. So, the distance moved by the raft in time t = 4.1 s is 5.04 m - 2.13 m = 2.91 m.
Since speed = distance/time, the raft's speed v = 2.91 m/4.1 s = 0.71 m/s
