We can solve this problem by using the impulse theorem, which states that the impulse exerted on the object (the product of the force exerted and the time) is equal to the change in momentum of the object:

$F \Delta t = m \Delta v$

where

F is the net force on the object

$\Delta t$ is the time

m is the mass

$\Delta v$ is the change in velocity

In this problem, we have:

m = 26.3 kg

$\Delta v = -21.0 m/s$

$\Delta t = 2.60 s$

Solving for F, we find

$F=\frac{m\Delta v}{\Delta t}=\frac{(26.3)(-21.0)}{2.60}=-212.4 N$

where the negative sign indicates that the direction of the force is opposite to the motion of the object.

Learn more about force and momentum:

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4 0

3 years ago

A charge Q experiences no net force at a particular point in space. Which of the following situations described below must ALWAY

laila [671]

Answer:

-There are no other charges nearby.

Explanation:

-There are no other charges nearby.

If there is no net charge in nearby space then the force on this charge will be ZERO

-If there are other charges nearby, they must all have the same sign as Q.

There there is nearby charge of same sign then it will have repulsion force on Q

-If there are other charges nearby, they must all have the opposite sign of Q.

if there is nearby charge of opposite sign then the force must be attraction force.

-If there are other charges nearby, the total positive charge must equal the total negative charge.

If there exist two type of charges nearby then there may exist either attraction or repulsion force on it

8 0

4 years ago