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3 years ago

Which officeholders are elected by the electoral college

Physics

1 answer:

NikAS [45]3 years ago

4 0

Answer:Electoral Vote

Explanation:i did it before

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Two cars bump going the same direction and stick together. Car A has a mass of 1000kg car B has a mass of 2000kg. What the speed

beks73 [17]

Answer:

I belive that the 2000 kg will be going faster then the 1000kg

Explanation:

Because it is 2x as heavy as the other car which means it most likely would hit the car and keep going because it can hit it so hard that the car dosent hit effected

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3 years ago

What process is used when the sun transfers light to plants

Anna71 [15]

Radiation is the correct answer

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3 years ago

When I double displacement reaction takes place, one of the products must be_______.

sattari [20]

Answer:

the answer would be Salt

Explanation:

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3 years ago

Read 2 more answers

A force of 100. newtons is used to move an object a distance of 15 meters with a power of 25 watts. Find the time it takes to do

Flauer [41]

<h3>It takes 60 seconds to do the work</h3>

Solution:

Given that,

Force = 100 newtons

Distance = 15 meters

Power = 25 watts

To find: time it takes to do the work

Find the work done:

$work = force \times displacement\\\\work = 100\ newtons \times 15\ meters\\\\work = 1500\ joule$

Find the time taken

$power = \frac{work}{time}\\\\25\ watts = \frac{1500\ joule}{time}\\\\time = \frac{1500\ joule}{25\ watt}\\\\time = 60\ second$

Thus it takes 60 seconds to do the work

3 0

3 years ago

In a thunderstorm, electric charge builds up on the water droplets or ice crystals in a cloud. Thus, the charge can be considere

jolli1 [7]

1) 333.6 C

In order to have breakdown, the electric field at the surface of the cloud must be equal to the breakdown electric field:

$E=3.00\cdot 10^6 N/C$

The electric field strength at the surface of a charged sphere is given by

$E=\frac{1}{4\pi \epsilon_0} \frac{Q}{R^2}$

where

$\epsilon_0 = 8.85\cdot 10^{-12} C^2/(N^2 m^2)$ is the vacuum permittivity

Q is the charge on the sphere

R is the radius of the sphere

Here we have a cloud of radius

$R = 1.00 km = 1000 m$

So we can re-arrange the previous equation in order to find the charge on the cloud:

$Q=4\pi \epsilon_0 ER^2=4\pi (8.85\cdot 10^{-12})(3.00\cdot 10^6)(1000)^2=333.6 C$

2) $2.08\cdot 10^{21}$ excess electrons

The total charge of the cloud must be (in magnitude)

Q = 333.3 C

We know that one electron carries a charge of

$e = 1.6 \cdot 10^{-19}C$

The total charge is just given by the charge of each electron multiplied by the number of excess electrons in the cloud:

$Q=Ne$

where

N is the number of excess electrons

Solving for N, we find:

$N=\frac{Q}{e}=\frac{333.3 C}{1.6\cdot 10^{-19} C}=2.08\cdot 10^{21}$

6 0

3 years ago