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agasfer [191]
3 years ago
5

Multiple-Concept Example 13 presents useful background for this problem. The cheetah is one of the fastest-accelerating animals,

because it can go from rest to 27 m/s (about 60 mi/h) in 4.0 s. If its mass is 110 kg, determine the average power developed by the cheetah during the acceleration phase of its motion. Express your answer in (a) watts and (b) horsepower.
Physics
1 answer:
erik [133]3 years ago
5 0

Answer:

Explanation:

given,

speed of cheetah = 27 m/s

time taken  = 4 s

mass of cheetah = 110 kg

a = \dfrac{27-0}{4}

a = 6.75 m/s²

v² = u² + 2 as

27² = 0 + 2 × 6.75× s

s = 54 m

a) power = \dfrac{work\ done}{t}

power = \dfrac{F.s}{t}

power = \dfrac{m.a.s}{t}

power = \dfrac{110\times 6.75\times 54}{4}

power = 10,023\ watt

b) power = \dfrac{10,023}{746}

   power = 13.46\ horsepower

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A girl drops a pebble from a high cliff into a lake far below. She sees the splash of the pebble hitting the water 2.00s later.
Natali5045456 [20]

Answer:

19.62 ms

Explanation:

t = Time taken = 2 s

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s² (downward direction is taken as positive)

Equation of motion

v=u+at\\\Rightarrow v=0+9.81\times 2\\\Rightarrow v=19.62\ m/s

The speed of the pebble when it hit the water is 19.62 ms

3 0
3 years ago
A completely inelastic collision occurs between two balls of wet putty that move directly toward each other along a vertical axi
Marrrta [24]

Answer:

h = 2.64 meters      

Explanation:

It is given that,

Mass of one ball, m_1=3\ kg

Speed of the first ball, v_1=20\ m/s (upward)

Mass of the other ball, m_2=2\ kg

Speed of the other ball, v_2=-12\ m/s (downward)

We know that in an inelastic collision, after the collision, both objects move with one common speed. Let it is given by V. Using the conservation of momentum to find it as :

V=\dfrac{m_1v_1+m_2v_2}{m_1+m_2}

V=\dfrac{3\times 20+2\times (-12)}{3+2}

V = 7.2 m/s

Let h is the height reached by the combined balls of putty rise above the collision point. Using the conservation of energy as :

mgh=\dfrac{1}{2}mV^2

h=\dfrac{V^2}{2g}

h=\dfrac{7.2^2}{2\times 9.8}

h = 2.64 meters

So, the height reached by the combined mass is 2.64 meters. Hence, this is the required solution.

5 0
3 years ago
A boat crosses a river of width 229 m in which the current has a uniform speed of 0.756 m/s. The pilot maintains a bearing (i.e.
Stolb23 [73]

Answer:

1.85 m/s

102.438 m

Explanation:

From vector motion

The resultant velocity

R=\sqrt{0.756^2+1.69^2}\\\Rightarrow R=1.85\ m/s

The magnitude of speed of the speed of the boat relative to a stationary shore observer is 1.85 m/s

The distance covered is 229 m

Time = Distance / Speed

\text{Time}=\frac{229}{1.69}\\\Rightarrow \text{Time}=135.50\ s

Distance = Speed of current × Time

Distance = 0.756×135.5 = 102.438 m

The boat will be 102.438 m from the initial position is the boat when it reaches the opposite shore

3 0
4 years ago
f a wave has a wavelength of 9 meters and a period of 0.006, what is the velocity of the wave? A. 1,200 m/s B. 1,500 m/s C. 1,80
GalinKa [24]

Answer: 1500 m/sec. ( b )

Solution:

V= f (λ)

Speed = frequency. Wavelength  

And frequency = 1/time period

First we will find the frequency :

Frequency = 1/time period

1/0.006 = 166.67 Hz

Using this in the equation:

Speed = frequency. Wavelength  

V= f (λ)

9 × 166.67  

= 1500.03 ≈ 1500

V (Speed) = 1500 m/s.

Note: Do not forget to mention the units or otherwise they may cost you marks!


6 0
3 years ago
Read 2 more answers
What is gravity?(20 points)
insens350 [35]

Answer:

The answere is A force that pulls objects toward the center of Earth

Explanation:

Hope this helpe! :)

8 0
3 years ago
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