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agasfer [191]
3 years ago
5

Multiple-Concept Example 13 presents useful background for this problem. The cheetah is one of the fastest-accelerating animals,

because it can go from rest to 27 m/s (about 60 mi/h) in 4.0 s. If its mass is 110 kg, determine the average power developed by the cheetah during the acceleration phase of its motion. Express your answer in (a) watts and (b) horsepower.
Physics
1 answer:
erik [133]3 years ago
5 0

Answer:

Explanation:

given,

speed of cheetah = 27 m/s

time taken  = 4 s

mass of cheetah = 110 kg

a = \dfrac{27-0}{4}

a = 6.75 m/s²

v² = u² + 2 as

27² = 0 + 2 × 6.75× s

s = 54 m

a) power = \dfrac{work\ done}{t}

power = \dfrac{F.s}{t}

power = \dfrac{m.a.s}{t}

power = \dfrac{110\times 6.75\times 54}{4}

power = 10,023\ watt

b) power = \dfrac{10,023}{746}

   power = 13.46\ horsepower

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A child drops a ball from a window. The ball strikes the ground in 3.0 seconds. What is the velocity of the ball the instant bef
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Answer:

29.396988 m/s

Explanation:

Really, it depends on where the child is when he drops the ball - e.g., which planet he is on, and his distance from the center of that planet.

I'll assume that the child is on Earth at sea level at the equator, so that his distance from the geocenter is 6378000 meters.

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Now, the above method is an approximation that makes the technically incorrect assumption that the acceleration of gravity is a constant throughout the entire fall. You get away with it because the drop is very short. In another situation, it might not be. So it would be nice to develop a more accurate method that does not assume constant gravitational acceleration. For that, we begin with the Vis Viva equation:

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a = the semimajor axis of a plunge orbit, which is equal to half of the apoapsis distance of 6378000+h, where

h = the altitude from which the ball is dropped

We can (using some math) develop the following equation:

t − t₀ = √[d/(2GM)] { √(rd−r²) + d arctan √(d/r−1) }

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Using an iterative method (e.g. Newton's or Danby's), we can determine that the altitude,

h = 44.0954 meters

So,

d = 6378044.09538 meters

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Now we can calculate that

v = 29.396988 m/s

This is the more nearly correct answer because it takes into account the variability of the gravitational acceleration during the fall.

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