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agasfer [191]
3 years ago
5

Multiple-Concept Example 13 presents useful background for this problem. The cheetah is one of the fastest-accelerating animals,

because it can go from rest to 27 m/s (about 60 mi/h) in 4.0 s. If its mass is 110 kg, determine the average power developed by the cheetah during the acceleration phase of its motion. Express your answer in (a) watts and (b) horsepower.
Physics
1 answer:
erik [133]3 years ago
5 0

Answer:

Explanation:

given,

speed of cheetah = 27 m/s

time taken  = 4 s

mass of cheetah = 110 kg

a = \dfrac{27-0}{4}

a = 6.75 m/s²

v² = u² + 2 as

27² = 0 + 2 × 6.75× s

s = 54 m

a) power = \dfrac{work\ done}{t}

power = \dfrac{F.s}{t}

power = \dfrac{m.a.s}{t}

power = \dfrac{110\times 6.75\times 54}{4}

power = 10,023\ watt

b) power = \dfrac{10,023}{746}

   power = 13.46\ horsepower

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An apple dropped from the branch of a tree hits the ground in 0.5 s. If the acceleration of the apple during its motion is 10 ms
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Given that,

Time = 0.5 s

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(I). We need to calculate the speed of apple

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Put the value into the formula

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(III). We need to calculate the height of the branch of the tree from the ground

Using equation of motion

s=ut+\dfrac{1}{2}gt^2

Put the value into the formula

s=0+\dfrac{1}{2}\times10\times(0.5)^2

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(II). We need to calculate the average velocity during 0.5 sec

Using formula of average velocity

v_{avg}=\dfrac{\Delta x}{\Delta t}

v_{avg}=\dfrac{x_{f}-x_{i}}{t_{f}-t_{0}}

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x_{i} = initial position

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Hence, (I). The speed of apple is 5 m/s.

(II). The average velocity during 0.5 sec is 2.5 m/s

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A flea jumps straight up to a maximum height of 0.400 m . what is its initial velocity v0 as it leaves the ground?
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For an object`s motion, the Kinematic equation is,

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