Answer:
19.62 ms
Explanation:
t = Time taken = 2 s
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration due to gravity = 9.81 m/s² (downward direction is taken as positive)
Equation of motion

The speed of the pebble when it hit the water is 19.62 ms
Answer:
h = 2.64 meters
Explanation:
It is given that,
Mass of one ball, 
Speed of the first ball,
(upward)
Mass of the other ball, 
Speed of the other ball,
(downward)
We know that in an inelastic collision, after the collision, both objects move with one common speed. Let it is given by V. Using the conservation of momentum to find it as :


V = 7.2 m/s
Let h is the height reached by the combined balls of putty rise above the collision point. Using the conservation of energy as :



h = 2.64 meters
So, the height reached by the combined mass is 2.64 meters. Hence, this is the required solution.
Answer:
1.85 m/s
102.438 m
Explanation:
From vector motion
The resultant velocity

The magnitude of speed of the speed of the boat relative to a stationary shore observer is 1.85 m/s
The distance covered is 229 m
Time = Distance / Speed

Distance = Speed of current × Time
Distance = 0.756×135.5 = 102.438 m
The boat will be 102.438 m from the initial position is the boat when it reaches the opposite shore
Answer: 1500 m/sec. ( b )
Solution:
V= f (λ)
Speed = frequency. Wavelength
And frequency = 1/time period
First we will find the frequency :
Frequency = 1/time period
1/0.006 = 166.67 Hz
Using this in the equation:
Speed = frequency. Wavelength
V= f (λ)
9 × 166.67
= 1500.03 ≈ 1500
V (Speed) = 1500 m/s.
Note: Do not forget to mention the units or otherwise they may cost you marks!
Answer:
The answere is A force that pulls objects toward the center of Earth
Explanation:
Hope this helpe! :)