The potential difference does work on the electron. The work is given by:
W = Vq
W = work, V = potential difference, q = electron charge
Given values:
V = 6V, q = 1.6x10^-19C
Plug in and solve for W:
W = 6(1.6x10^-19)
W = 0.96aJ
Answer:
Explanation:
given,
In first case Volume remains constant.
Work done in the first case is zero.
In Second case Volume change
V₁ = 0.2 m³
V₂ = 0.11 m³
Pressure, P = 5.5 x 10⁵ Pa
Work done = Pressure x change in volume
W = P ΔV
Hence, Work done when volume changes is equal to
Answer:
If the ray of light is deflected by 45 degrees by the first mirror its total deflection by mirror (I) is 90 deg. (incident = 45 and exit ray equals 45 deg)
The second mirror will cause a net deflection of 90 degrees and the total deflection will be 180 deg or in opposite direction to the incident ray.
