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Elza [17]
4 years ago
15

A person in bare feet is standing under a tree during a thunderstorm, seeking shelter from the rain. A lightning strike hits the

tree. A burst of current lasting 43 µs passes through the ground; during this time the potential difference between his feet is 21 kV. If the resistance between one foot and the other is 550 Ω,
what is the current through his body and how much energy is dissipated in his body by the lightning?
Physics
1 answer:
Anni [7]4 years ago
5 0

Answer:

I=38.181\ A is the current through the body of the man.

E=34.5\ J energy dissipated.

Explanation:

Given:

  • time for which the current lasted, t=43\times 10^{-6}\ s
  • potential difference between the feet, V=21000\ V
  • resistance between the feet, R=550\ \Omega

<u>Now, from the Ohm's law we have:</u>

I=\frac{V}{R}

I=\frac{21000}{550}

I=38.181\ A is the current through the body of the man.

<u>Energy dissipated in the body:</u>

E=I^2.R.t

E=38.181^2\times 550\times 43\times 10^{-6}

E=34.5\ J

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If a 2 kg block of aluminium (SHC: 921 J/kg°C) is heated from 20°C to 40°C, how much energy was transferred to it?
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H = mc∆T

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H = 2*921*(40-20)

H = 36840J

H = 36.84KJ

The energy transferred to it is 36.84KJ

4 0
3 years ago
A solid sphere, solid cylinder, and a hollow pipe all have equal masses and radii and are of uniform density. If the three are r
scZoUnD [109]

Answer:

A )  SOLID SPHERE

Explanation:

Moment of inertia of solid sphere = 2/5 M R²

= M K² , K is called radius of gyration

K = √2/5 R

Moment of inertia of solid cylinder = 1/2  M R²

= M K² , K is called radius of gyration

K = 1 /√2  R

Moment of inertia of solid sphere =  M R²

= M K² , K is called radius of gyration

K =  R

For rolling on inclined plane , acceleration  

a = \frac{gsin\theta}{1+\frac{K^2}{R^2} }

Putting the value of K for solid sphere

a for solid sphere

a = g sinθ / ( 1 +2/5)

a = .714 g sinθ

Putting the value of K for solid cylinder

a for solid cylinder

a = g sinθ / ( 1 +1/2)

a = .666 g sinθ

Putting the value of K for hollow pipe

a for hollow pipe

a = g sinθ / ( 1 +1 )

a = . 5 g sinθ

So we see that acceleration a for solid sphere is greatest and a for hollow pipe is the least. Hence solid sphere will reach the bottom earliest and hollow pipe will reach the bottom the latest.

7 0
3 years ago
Assume the average value of the vertical component of Earth's magnetic field is 42 μT (downward) in some region that has an area
Oliga [24]

Answer:

The net magnetic flux through the rest of Earth's surface is  5.782\times10^{-2}\ T

Explanation:

Given that,

Magnetic field = 42 μT

Area A=3.71\times10^{5}\ km^2

A=3.71\times10^{11}\ m^2

We need to calculate the flux per unit area

flux\ per\ unit\ area=\dfrac{42\times10^{-6}}{3.71\times10^{11}}

flux\ per\ unit\ area=1.132\times10^{-16}\ T/m^2

We need to calculate the total earth's surface area

A'=4\pi r^2

A'=4\times\pi\times(6.3781\times10^{6})^2

A'=5.1120\times10^{14}\ m^2

We need to calculate the rest of earth's area

A''=A-A'

Put the value into the formula

A''=5.1120\times10^{14}-3.71\times10^{11}

A''=5.10829\times10^{14}\ m^2

We need to calculate the net magnetic flux through the rest of Earth's surface

B'=5.10829\times10^{14}\times1.132\times10^{-16}

B'=5.782\times10^{-2}\ T

Hence, The net magnetic flux through the rest of Earth's surface is  5.782\times10^{-2}\ T

3 0
4 years ago
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