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Tanya [424]
1 year ago
10

find the density, in g/cm3g/cm3 , of a metal cube with a mass of 50.3 gg and an edge length (l)(l) of 2.65 cmcm . for a cube v

Physics
1 answer:
Alina [70]1 year ago
4 0

The density of the metal cube is 2.703 g/cm³.

The mass of a metal cube is m =50.3 grams.

The edge length of the metal cube is l = 2.65 cm.

Now, the density (ρ) of a cube can be given as:

ρ = m/(a)³

Where (a)³ is the volume of the cube, m is the mass of the cube, ρ is the density of the cube, and a is the length of one side of the cube.

Since the sides of a cube are equal therefore the value of a is the same for each edge length of the cube.

Now, the density of the metal cube in g/cm³ is:

ρ = m / a³

ρ = m / l³

ρ = 50.3 g / (2.65 cm)³

ρ = 50.3 g / (2.65 cm)(2.65 cm)(2.65 cm)

ρ = 50.3 g / 18.609 cm³

ρ = 2.703 g/cm³

Learn more about density here:

brainly.com/question/1354972

#SPJ4

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A 50 kg pitcher throws a baseball with a mass of 0. 15 kg. If the ball is thrown with a positive velocity of 35 m/s and there is
dsp73

The velocity of the pitcher at the given mass is 0.1 m/s.

The given parameters:

  • <em>Mass of the pitcher, m₁ = 50 kg</em>
  • <em>Mass of the baseball, m₂ = 0.15 kg</em>
  • <em>Velocity of the ball, u₂ = 35 m/s</em>

<em />

Let the velocity of the pitcher = u₁

Apply the principle of conservation of linear momentum to determine the velocity of the pitcher as shown below;

m₁u₁ = m₂u₂

u_1 = \frac{m_2 u_2}{m_1} \\\\u_1 = \frac{0.15 \times 35}{50} \\\\u_1 = 0.105 \ m/s\\\\u_1 \approx 0.1 \ m/s

Thus, the velocity of the pitcher at the given mass is 0.1 m/s.

Learn more about conservation of linear momentum here: brainly.com/question/13589460

4 0
2 years ago
Write a difference between force and work? ​
Nesterboy [21]

Answer:

force is a derived quantity

work is a fundamental quantity

2.Force is measured in Newton why work is measured in Newton per seconds (N/s)

Explanation:

no

3 0
2 years ago
Read 2 more answers
Un alambre de teléfono de 120m de largo y de 2.2mm de diámetro se estira debido a una fuerza de 380 N cual es el esfuerzo longit
sergij07 [2.7K]

Respuesta: verifique amablemente la explicación

Explicación:

Dado lo siguiente:

Longitud (L) del cable = 120 m

Diámetro (d) = 2,2 mm (2,2 / 1000) = 2,2 * 10 ^ -3 m

Fuerza (F) = 380 N

Esfuerzo longitudinal = Fuerza / Área

Área = πd² / 4 = (π * (2.2 * 10 ^ -3) ^ 2) / 4

Área = (3.142 * 4.84 * 10 ^ -6)

Área = 0.00000380132 m²

Estrés = Fuerza / Área

Estrés = 380 / 0.00000380132

Esfuerzo longitudinal = 99952128.12 = 9.9952128 * 10^7 Nm^-2

Deformación longitudinal: extensión / longitud

Extensión = 0.10 m

Longitud = 120 m

Deformación longitudinal = 0,1 m / 120 m

Deformación longitudinal = 0.0008333 = 8.33 × 10 ^ -4

6 0
2 years ago
A mule pulls a cart of milk 10 meters with a force of 50 Newton's.Calculate the work done by a mule
san4es73 [151]

Work = Force x Distance

Assuming that this work is being done parallel to the displacement that is, but under that assumption:

W = (50)(10)

W = 500 J

8 0
3 years ago
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Jack and George meet in the middle of a lake while paddling in their canoes. They come to a complete stop and talk for a while.
spayn [35]

Answer:

momentum =0

kinetic energy >0, positive

Explanation:

The final momentum is zero but the final kinetic energy is positive. The momentum is zero because momentum is the sum of the mass×velocity for each component. momentum is conserved

The KE is positive because KE is the sum of the 1/2×mass×velocity^2.

Whereas velocity can be positive and negative since it is (it's what makes the momentum zero because on is positive and one is negative), the velocity squared will always be positive.

Adding together two positives will always be a positive number.

4 0
3 years ago
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