Question

find the density, in g/cm3g/cm3 , of a metal cube with a mass of 50.3 gg and an edge length (l)(l) of 2.65 cmcm . for a cube v

Answer 1

The density of the metal cube is 2.703 g/cm³.

The mass of a metal cube is m =50.3 grams.

The edge length of the metal cube is l = 2.65 cm.

Now, the density (ρ) of a cube can be given as:

ρ = m/(a)³

Where (a)³ is the volume of the cube, m is the mass of the cube, ρ is the density of the cube, and a is the length of one side of the cube.

Since the sides of a cube are equal therefore the value of a is the same for each edge length of the cube.

Now, the density of the metal cube in g/cm³ is:

ρ = m / a³

ρ = m / l³

ρ = 50.3 g / (2.65 cm)³

ρ = 50.3 g / (2.65 cm)(2.65 cm)(2.65 cm)

ρ = 50.3 g / 18.609 cm³

ρ = 2.703 g/cm³

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