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3 years ago

Compare the inertia of a car to the inertia of a bicycle

Physics

2 answers:

Lana71 [14]3 years ago

8 0

The car has more inertia than the bike. Why? Because the car has a greater mass than the bicycle.

Nastasia [14]3 years ago

7 0

Answer:

The inertia of a car is more than the inertia of a bicycle.

Explanation:

Inertia of an object is its inherited property. It is the measure of its mass. It is clear that the inertia of an object depends directly on its mass. Mass of an object is the amount of matter contained in it. It is same at every location.

For example, if we move from one planet to another, the mass of an object remains the same while its weight changes. It is clear that the mass of car is more than the mass of bicycle. As a result, the inertia of a car is more than the inertia of a bicycle.

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A car is traveling at 30m/s it accelerates steadily for 5 s after which it is travelling at 50 m/s calculate its acceleration?

Natalka [10]

Formula for acceleration: a = v-v0/t
a is acceleration, v is final velocity and v0 is starting velocity, t is time
Now plug it in
a = 50m/s - 30 m/s = 20 m/s/ 5s = 4 m/s^2
The acceleration is 4 m/s^3

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3 years ago

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A pencil rolls horizontally of a 1 meter high desk and lands .25 meters from the base of the desk. How fast was the pencil rolli

vovikov84 [41]

Answer: 0.55 m/s

Explanation:

This situation is related to projectile motion (also called parabolic motion), where the main equations are as follows:

$x=V_{o} cos\theta t$ (1)

$y=y_{o}+Vo sin \theta t + \frac{g}{2}t^{2}$ (2)

Where:

$x=0.25 m$ is the horizontal displacement of the pencil

$V_{o}$ is the pencil's initial velocity

$\theta=0\°$ since we are told the pencil rolls <u>horizontally</u> before falling

$t$ is the time since the pencil falls until it hits the ground

$y_{o}=1 m$ is the initial height of the pencil

$y=0$ is the final height of the pencil (when it finally hits the ground)

$g=-9.8m/s^{2}$ is the acceleration due gravity, always acting vertically downwards

Begining with (1):

$x=V_{o} cos(0\°) t$ (3)

$x=V_{o}t$ (4)

Finding $t$ from (2):

$0=1 m+ \frac{-9.8m/s^{2}}{2}t^{2}$ (5)

$t=\sqrt{\frac{-2y_{o}}{g}}$ (6)

Substituting (6) in (4):

$x=V_{o}\sqrt{\frac{-2y_{o}}{g}}$ (7)

Isolating $V_{o}$ :

$V_{o}=\frac{x}{\sqrt{\frac{-2y_{o}}{g}}}$ (8)

$V_{o}=\frac{0.25 m}{\sqrt{\frac{-2(1 m)}{-9.8m/s^{2}}}}$ (9)

Finally:

$V_{o}=0.55 m/s$

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4 years ago

The maximum mass of a white dwarf is ______ times the mass of the sun.

Savatey [412]

Answer:

(A)

Explanation:

about 1.4 times the mass of our sun.

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3 years ago

Precision measurements of the acceleration due to gravity show that the acceleration is slightly different in different location

DochEvi [55]

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4 years ago

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prohojiy [21]

Answer:

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3 years ago