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3 years ago

How do you change Celsious to Faranheight (or however u write them)

2 answers:

7 0

So there’s two options for the formula!
The temperature T in degrees Fahrenheit (°F) is equal to the temperature T in degrees Celsius (°C) times 9/5 plus 32:

T(°F) = T(°C) × 9/5 + 32
or
T(°F) = T(°C) × 1.8 + 32

Minchanka [31]3 years ago

5 0

Multiply by 1.8 and then add 32.

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Which scientist was the first to practice the scientific method we use today

bixtya [17]

Answer:

Aristotle

Explanation:

6 0

3 years ago

011 1.0 points What energy change is associated with the reaction to obtain one mole of H2 from one wang (ew22622) – 19D Thermod

vlada-n [284]

Answer:

249 kJ

Explanation:

To obtain the energy change of the reaction:

H₂O → H₂ + ¹/₂ O₂

It is necessary to obtain the difference between bond energy of the products and bond energy of the reactant, thus:

Energy of products:

1 mol of H-H bond × 436 kJ/mol = 436 kJ

¹/₂ mol of O=O bond × 498 kJ/mol = 249 kJ

Energy of reactant:

2 mol of H-O bond × 467 kJ/mol = 934 kJ

Energy change of the reaction is:

934 kJ - (436 kJ + 249 kJ) = 249 kJ

I hope it helps!

4 0

3 years ago

17.The formation of steam above a pot of water is an example of

sweet [91]

#1...Evaporation
#2....Gas

8 0

3 years ago

There is enough energy in air at room temperature to change some

Pavel [41]

Answer:

Explanation:

There is enough energy in air at room temperature to change some liquids to gases. The temperature of ice water is lower than the temperature of dry ice in alcohol. Carbon dioxide can change directly from the solid phase to the gaseous phase. ... Absolute zero is the temperature at which there is no molecular motion.

Answer: True

8 0

3 years ago

2p is the correct representation for the sub-shell with n = 2 and l = 1.

boyakko [2]

Explanation:

Principle Quantum Numbers : It describes the size of the orbital and the energy level. It is represented by n. Where, n = 1,2,3,4....

Azimuthal Quantum Number : It describes the shape of the orbital. It is represented as 'l'. The value of l ranges from 0 to (n-1). For l = 0,1,2,3... the orbitals are s, p, d, f...

s = 1 orbital

p = 3 orbitals

d = 5 orbitals

f = 7 orbitals

For n = 4

l = 0 to (n-1) = 0 to 3 = (4s , 4p , 4d , 4f)

Number of subshells = 4

Number of orbitals = 1 + 3 + 5 + 7 = 16

The maximum number of electrons the n = 4 shell can contain:

Each orbital can holds upto two electrons, then 16 orbitals will have :

$16\times 2=32$

32 is the maximum number of electrons the n = 4 shell can contain

6 0

4 years ago

Read 2 more answers