In a vacuum, all objects fall at the same rate. Meaning that the 100 kg ball will fall at the same speed as the 10 kg ball. Assuming that both objects share the same starting acceleration, they will keep that acceleration until the fall is stopped.
In other words, your answer is the first one, Both objects will accelerate at 9.8 m/s
Answer:
option A
Explanation:
given,
Force = F
angle = θ
weight on suitcase = mg
distance = d
constant velocity so, acceleration a = 0
coefficient of friction = µ
Work done = ?
Work done is equal to force into displacement.
Friction act opposite to the force acting so, work done by frictional force will be negative.
frictional force will act into horizontal direction opposite to force.
here displacement is equal to d
now,
W = -F d cos θ
Hence,the correct answer is option A
It IS <span>PE = (1200 kg)(9.8 m/s²)(42 m) = 493,920 J </span>
Answer:
Given:
Mass of elephant = 5240 kg
The initial speed of the elephant = 4.55 m/s
Mass of the rubber ball, m, = 0.15 kg
Inital speed of the rubber ball, v = 7.81 m/s
On substitution in
=
+ ![[\frac{m_{2}-m_{1}}{m_{1}+m_{2} } ] v_{2f}](https://tex.z-dn.net/?f=%5B%5Cfrac%7Bm_%7B2%7D-m_%7B1%7D%7D%7Bm_%7B1%7D%2Bm_%7B2%7D%20%20%7D%20%5D%20v_%7B2f%7D)
=
+ ![[\frac{0.15_{}-5240_{}}{5240_{}+0.15_{} } ] (7.81_{})](https://tex.z-dn.net/?f=%5B%5Cfrac%7B0.15_%7B%7D-5240_%7B%7D%7D%7B5240_%7B%7D%2B0.15_%7B%7D%20%20%7D%20%5D%20%287.81_%7B%7D%29)
a) The negatıve sign shows that the ball bounces back in the direction opposite to the incident
b) it is clear that the velocity of the ball increases and therefore it is kinetic energy
. The ball gains kinetic energy from the elephant.