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3 years ago

This is the SI unit for force meter liter Newton m/s/s

1 answer:

4 0

The newton is the SI unit for force; it is equal to the amount of net force required to accelerate a mass of one kilogram at a rate of one meter per second squared. Newton's second law of motion states: F = ma, multiplying m (kg) by a (m/s 2 ).

I don't understand your question, but I think that would help.

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Never mind wrong question

Leokris [45]

Its okay my friend. you dont need to over stress it.

7 0

3 years ago

Read 2 more answers

Natural gas is stored in a spherical tank at a temperature of 13°C. At a given initial time, the pressure in the tank is 117 kPa

drek231 [11]

Answer:

1. the absolute pressure in the tank before filling = 217 kPa

2. the absolute pressure in the tank after filling = 312 kPa

3. the ratio of the mass after filling M2 to that before filling M1 = 1.44

The correct relation is option c ( $\frac{M_{2} }{M_{1} } = \frac{P_{2} T_{1} }{P_{1} T_{2} }$ )

Explanation:

To find -

1. What is the absolute pressure in the tank before filling?

2. What is the absolute pressure in the tank after filling?

3. What is the ratio of the mass after filling M2 to that before filling M1 for this situation?

As we know that ,

Absolute pressure = Atmospheric pressure + Gage pressure

So,

Before filling the tank :

Given - Atmospheric pressure = 100 kPa , Gage pressure = 117 kPa

⇒Absolute pressure ( p1 ) = 100 + 117 = 217 kPa

Now,

After filling the tank :

Given - Atmospheric pressure = 100 kPa , Gage pressure = 212 kPa

⇒Absolute pressure (p2) = 100 + 212= 312 kPa

Now,

As given, volume is the same before and after filling,

i.e. $V_{1}$ = $V_{2}$

As we know that, P ∝ M

⇒ $\frac{p_{1} }{p_{2} } = \frac{m_{1} }{m_{2} }$

⇒ $\frac{m_{2} }{m_{1} } = \frac{p_{2} }{p_{1} }$

⇒ $\frac{m_{2} }{m_{1} } = \frac{312 }{217 } = 1.4378$ ≈ 1.44

Now, as we know that PV = nRT

As V is constant

⇒ P ∝ MT

⇒ $\frac{P}{T}$ ∝ M

⇒ $\frac{M_{2} }{M_{1} } = \frac{P_{2} T_{1} }{P_{1} T_{2} }$

So, The correct relation is c option.

6 0

3 years ago

Will bromine react with sodium

denis-greek [22]

Yes. bromine and sodium iodide can react to form sodium bromine and free iodine

4 0

3 years ago

When 150. g zinc sulfide are burned in excess oxygen, 68.5 g of zinc oxide are actually produced, along with sulfur dioxide. Det

Bumek [7]

%yield = 54.6%

<h3>Further explanation</h3>

Percent yield is the compare of the amount of product obtained from a reaction with the amount you calculated

(theoretical)

General formula:

Percent yield = (Actual yield / theoretical yield )x 100%

<h3 />

Reaction

2ZnS+3O₂ ⇒ 2ZnO+2SO₂

MW ZnS = 97.474 g/mol

mol ZnS

$\tt \dfrac{150}{97.474}=1.54$

MW ZnO = 81.38 g/mol

mol ZnO (from mol ZnS as limiting reactant, O₂ excess)

$\tt \dfrac{2}{2}\times 1.54=1.54$

Actual ZnO produced

$\tt 1.54\times 81.38=125.33~g$

Theoretical production = 125.388

%yield

$\tt \dfrac{68.5}{125.33}\times 100\%=\boxed{\bold{54.6\%}}$

4 0

3 years ago

According to the molecular orbital energy-level diagram below, which one of the following statements is not correct about NO, NO

Lubov Fominskaja [6]

None of the statement is not correct about NO, NO+, and NO−.

Explanation:

Those molecules whose all subshells are completely filled are diamagnetic.

Those molecules whose any sub-shell is incomplete is termed paramagnetic.

Let us check the magnetism in all three molecules based on molecular orbital theory and Lewis structure

NO= number of electrons 11

It form N=O having configuration 1s2,2s2,2p6,3s1, it has 1 unpaired electron so it is paramagnetic.

Now NO-, number of electrons 12 having configuration 1s2,2s2,2p6,3s2, no unpaired electron hence dimagnetic.

Now NO+, number of electrons is 10 having configuration 1s2,2s2,2p6,3s2, dimagnetic

Let us calculate the bond order of NO-

N0- have 12 electrons as 5 of nitrogen, 6 of oxygen and 1 of - charge on oxygen.

So, bond order = $\frac{8-4}{2}$

= 2 double bonds

bond order of NO+, Number of electrons is 10

bond order= $\frac{8-2}{2}$

bond order = 3

bond order of NO, number of electrons 11

bond order= $\frac{8-3}{2}$

bond order=2.5

Larger the bond order shorter the bond.

4 0

3 years ago