Answer:
Option C. 0.34 moles
Explanation:
Data obtained from the question include:
Molarity = 0.15M
Volume = 2.25L
Mole =
Molarity = mole /Volume
Mole = Molarity x Volume
Mole = 0.15 x 2.25
Mole = 0.34mole
The number of mole of AlCl3 present in the solution is 0.34mole.
First is homogeneous and so is the third. second is heterogeneous
There is 1 OH- in 1 molecule of NaOH.
Also, there is 1 H+ in 1 molecule of lactic acid.
So the reaction is simple.
so just equate the moles
moles of OH- in NaOH = moles of H+ in lactic acid
26.8 x 0.07 = 250 x Mole of lactic
Moles of lactic = 0.0075
so mass = 0.0075 x 90.8 = 0.681 g
Answer:
year 1 is 5.5%
year 2 is 7.5%
year 3 is 10.2%
Explanation:
since,
length of the transect covered in seaweed / total lenth of transect x 100
then,
0.55 / 10.0 x 100 = 5.5
and
0.75 / 10.0 x 100 = 7.5
and
1.02 / 10.0 x 100 = 10.2
you could also just move the decimal to the right once
:)
