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Serga [27]
4 years ago
6

Popeye wants to make a dilute spinach solution for Sweetpea's bottle. How much 3.0 M spinach solution should he add to the 500.0

mL bottle if he wants the final solution to be 0.30 M?
Chemistry
1 answer:
Lynna [10]4 years ago
8 0

Answer : The volume of 3.0 M spinach solution added should be, 50 mL

Explanation :

Formula used :

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the initial molarity and volume of spinach solution.

M_2\text{ and }V_2 are the final molarity and volume of diluted spinach solution.

We are given:

M_1=3.0M\\V_1=?\\M_2=0.30M\\V_2=500.0mL

Now put all the given values in above equation, we get:

3.0M\times V_1=0.30M\times 500.0mL\\\\V_1=50mL

Hence, the volume of 3.0 M spinach solution added should be, 50 mL

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Trimix 10/50 is a gas mixture that contians 10% oxygen and 50% helium, and the rest is nitrogen. If a tank of trimix 10/50 has a
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Answer: 1.61 x 10⁴ kPa

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In the Trimix 10/50 mix you have 10% oxygen, 50% helium and 40% nitrogen.

To calculate the total number of moles of the mixture and thus determine the molar fraction of helium, we consider 100 g and calculate the number of moles that represent 10 g of O₂ (n₁), 50 g of He (n₂) and 40 g of N₂ (n₃):

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n₂ =  50 g x \frac{1 mol}{8.005 g} = 6.246 mol

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nt = n₁ + n₂ + n₃ = 0.313 mol + 6.246 mol +1.428 mol

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x₂ =  \frac{6.246 mol}{7.987 mol} = 0.78

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P₂ = x₂ P = 0.78 x 2.07 x 10⁴ kPa

P₂= 1.61 x 10⁴ kPa

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