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denpristay [2]
3 years ago
11

How many molecules of water are released during the polymerization of a 20 monomer-long cellulose molecule?

Chemistry
1 answer:
Alborosie3 years ago
8 0

Answer:

  • <em>During the polymerization of a 20 monomer-long cellulose molecule,</em> <u>19 molecules of water are released.</u>

<u></u>

Explanation:

In simple terms, <em>cellulose </em>is the biopolymer formed by many glucose units. This is cellulose is the polymer and glucose is the monomer.

To have a <em>20 monomer-long cellulose molecule</em>, 20 monomers have been chemically bonded by reacting 19 times, as it is explained in the next paragrpahs, and so 19 molecules of water have been released.

You can imaging the polymerization process as a step-by-step reaction in which the first step is the condensation reaction of one glucose molelecule to produce a 2 monomer-long chain, with the release of one molecule of water: the second step would be the condensation reaction between the 2 monomer-long chain with another glucose molecule, with the release of an additional molecule of water, and so on, until 19 condensation reactions happen, to obtain the 20 monomer-long cellulose molecule.

Condensation is the loss of water in a chemical reaction.

When two glucose molecules react together, condensation occurs. One OH group from each glucose molecule come together, the OH from one glucose molecule combines with the H part of the OH from the other glucose molecule, to form H₂O (water that is released).

The two glucose molecules (monomers) will form one bigger molecule where the two glucose monomers are bonded through the oxygen atom that did not form part of the water molecule released.

Then, a 20-monomer chain means 19 condenstation reactions, with the release of 19 molecules of water.

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The number of moles of c atoms in 3.20 moles of c2h60
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What mass of Na2SO4is needed to make 2.5 L of 2.0 Msolution? (Na = 23 g; S = 32 g; O = 16 g)
ivanzaharov [21]

Answer:

mass (g) needed = 710.2 grams Na₂SO₄(s)

Explanation:

Needed is 2.5 Liters of 2.0M Na₂SO₄; formula wt Na₂SO₄ = 142.04g/mol.

mass (grams) of Na₂SO₄(s) = Molarity needed x Volume needed in Liters x Formula Wt of solute

mass (grams) of Na₂SO₄(s) = (2.5L)(2.0M)(142.04g/mol) = 710.2 grams Na₂SO₄(s)

Mixing: Transfer 710.4 grams Na₂SO₄ into mixing vessel and add water-solvent up to but not to exceed 2.5 Liters total volume. Mix until dissolved.

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5 0
2 years ago
6/10
hichkok12 [17]

Answer: B

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5 0
3 years ago
You find a ring with a mass of 107g . You fill a graduated cylinder up with 10ml of water and put the ring into the cylinder . T
Korvikt [17]

Answer:

5 mL

Explanation:

Given data:

mass of ring = 107 g

volume of water = 10 mL

increase in volume = 15 mL

How much water displace = ?

Solution:

V (ring) = V (water + ring) - V (water)

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when the ring is put into cylinder, volume is increased by 15 mL. The volume of water was 10 mL so water is displaced by 5 mL and the volume 5mL is the voulme of ring.

3 0
3 years ago
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