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Lunna [17]
3 years ago
15

All atoms of the same element must have the same number of what?

Chemistry
2 answers:
Pavel [41]3 years ago
6 0

Answer:

A.

Explanation:

i just took the test and chose A.protons. lily~chan hopes she helps

torisob [31]3 years ago
3 0

Answer:

A. protons

I hope this helps!

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Would you classify the atoms in the table as pure substances?
ivann1987 [24]

Answer:

Yes

Explanation:

Atoms are generally classified as pure substances. A pure substance has the following properties:

  • All parts are the same throughout i.e. homogeneous
  • They have definite composition
  • The cannot easily be broken down into simpler substances by physical means.
  • Separation by physical methods is not easy.
  • They have unique sets of physical properties.

Elements and compounds are generally classified as pure substances. Since atoms are the building blocks of pure substances, they can be classified as one.

3 0
3 years ago
What does semi-preamble mean
enyata [817]
Llowing certain substances to pass through it but not others, especially allowing the passage of a solvent but not of certain solutes.
3 0
3 years ago
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PLS HELP! If I have 17 moles of gas at a temperature of 67°C, and a pressure of 5.34 atmospheres, what is the volume of the gas?
sveta [45]

Answer: If I have 17 moles of gas at a temperature of 67°C, and a pressure of 5.34 atmospheres, what is the volume of the gas? write down all the givens of the problem

8 0
3 years ago
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What is the standard gibbs free energy for the transformation of diamond to graphite at 298 k? cdiamondâcgraphite?
denis-greek [22]
Considering; graphite; standard enthalpy = 0 and entropy = 5.740; diamond standard enthalpy = 1.897 and entropy = 2.38.
Using the equation Delta G = Delta H - Temperature (DeltaS)
Delta H = enthalpy sum of products - enthalpy sum of reactants
Which will be; 0 -1.897 = -1.897 kJ/Mol
Delta S is the entropy sum; given by 
5.740 - 2.38 = 3.36 J/Mol
We can convert Delta S from Joules to kilo Joules by dividing by 1000
we get ; 0.00336 kJ/mol
We are given a temperature in kelvin which suits the calculations ((298 k)
Therefore; using the equation; 
= -1.897 - (298 × 0.00336) = -2.90 kJ
Thus; the standard gibbs free energy will be; -2.9 kJ

5 0
3 years ago
You decide you want to carry a boulder home from the beach. It is 20 centimeters on each
e-lub [12.9K]

Answer:

Weight of boulder = 22,400 gram

Explanation:

Given:

Volume = 8,000 cm³

Density = 2.8

Find:

Weight of boulder

Computation:

Weight of boulder = Volume x Density

Weight of boulder = 8,000 x 2.8

Weight of boulder = 22,400 gram

3 0
3 years ago
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