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3 years ago

What is the percent by mass of oxygen in fe2o3

2 answers:

5 0

To get the formula mass we have to add the atomic mass of each atom
(55.847 x 2) + ( 16 x 3) = 160
this means that 16 x 3 = 48 are the grams of O
% = 48 x 100 / 160 =30 %

hope this helped mark me brainliest

anygoal [31]3 years ago

4 0

30% is the answer. Good luck

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The change in internal energy for the combustion of 1.0 mol of octane at a pressure of 1.0 atm is -5084.1 kj . f the change in e

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Given:

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3 years ago

A gas is collected in a 34.3L container at a temperature of 31.5°C. Later, the container has a volume of 29.2L, a temperature of

goldenfox [79]

Answer:

108 kPa

Step-by-step explanation:

To solve this problem, we can use the Combined Gas Laws:

p₁V₁/T₁ = p₂V₂/T₂ Multiply each side by T₁

p₁V₁ = p₂V₂ × T₁/T₂ Divide each side by V₁

p₁ = p₂ × V₂/V₁ × T₁/T₂

Data:

p₁ = ?; V₁ = 34.3 L; T₁ = 31.5 °C

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Calculations:

(a) Convert temperatures to kelvins

T₁ = (31.5 + 273.15) K = 304.65 K

T₂ = (21.0 + 273.15) K = 294.15 K

(b) Calculate the pressure

p₁ = 122.2 kPa × (29.2/34.3) × (304.65/294.15)

= 122.2 kPa × 0.8542 × 1.0357

= 108 kPa

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