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Rufina [12.5K]
3 years ago
7

What is the percent by mass of oxygen in fe2o3

Chemistry
2 answers:
Effectus [21]3 years ago
5 0
To get the formula mass we have to add the atomic mass of each atom
(55.847 x 2) + ( 16 x 3) = 160
this means that 16 x 3 = 48 are the grams of O
% = 48 x 100 / 160 =30 %

hope this helped mark me brainliest
anygoal [31]3 years ago
4 0
30% is the answer. Good luck
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The change in internal energy for the combustion of 1.0 mol of octane at a pressure of 1.0 atm is -5084.1 kj . f the change in e
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<u>Given:</u>

Change in internal energy = ΔU = -5084.1 kJ

Change in enthalpy = ΔH = -5074.3 kJ

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<u>Explanation:</u>

Based on the first law of thermodynamics,

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3 years ago
A gas is collected in a 34.3L container at a temperature of 31.5°C. Later, the container has a volume of 29.2L, a temperature of
goldenfox [79]

Answer:

108 kPa  

Step-by-step explanation:

To solve this problem, we can use the <em>Combined Gas Laws</em>:

p₁V₁/T₁ = p₂V₂/T₂             Multiply each side by T₁

   p₁V₁ = p₂V₂ × T₁/T₂      Divide each side by V₁

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Data:

p₁ = ?;                 V₁ = 34.3 L; T₁ = 31.5 °C

p₂ = 122.2 kPa; V₂ = 29.2 L; T₂ = 21.0 °C

Calculations:

(a) Convert temperatures to <em>kelvins </em>

T₁ = (31.5 + 273.15) K = 304.65 K

T₂ = (21.0 + 273.15) K = 294.15 K

(b) Calculate the <em>pressure </em>

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   = 122.2 kPa × 0.8542 × 1.0357

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3 years ago
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