Answer:
4.78atm
Explanation:
From the question, we obtained the following:
P1 (initial pressure) = 3.5 atm
T1 (initial temperature) = 200K
T2 (final temperature) = 273K
P2 (final pressure) =?
Using P1/T1 = P2/T2, the final pressure can be obtained as shown below:
P1/T1 = P2/T2
3.5/200 = P2/273
Cross multiply to express in linear form as shown below:
200 x P2 = 3.5 x 273
Divide both side by 200
P2 = (3.5 x 273)/200
P2 = 4.78atm
Therefore, the pressure at 273K is 4.78atm
Answer:
condensation
Explanation:
The process of a gas becoming a liquid is called condensation.
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The mass of butane gas at the given volume and Standard temperature and pressure is 0.0022g.
<h3>What is Ideal Gas Law?</h3>
The Ideal gas law or general gas equation emphasizes on the state or behavior of a hypothetical ideal gas. It states that "the pressure multiplied by volume is equal to moles multiply by the universal gas constant multiply by temperature.
It is expressed as;
PV = nRT
Where P is pressure, V is volume, n is the amount of substance, T is temperature and R is the ideal gas constant ( 0.08206 Latm/molK )
Given the data in the question;
- Volume of the gas V = 3L
- At STP; P = 1.0atm, T = 273.15K
- Amount of gas n = ?
PV = nRT
n = PV / RT
n = ( 1.0atm × 3.00L ) / ( 0.08206 Latm/molK × 273.15K )
n = 3.00Latm / 22.41 Latm/mol
n = 0.13mol
Now, since Molar mass of brutane gas is 58.12 g/mol.
Mass = n × Molar mass
Mass = 0.13mol × 58.12 g/mol
Mass = 0.0022g
Therefore, the mass of butane gas at the given volume and Standard temperature and pressure is 0.0022g.
Learn more about Ideal Gas Law here: brainly.com/question/4147359
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